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3 years ago

10

Simplify the mathematical expressions to determine the product or quotient in scientific notation. Round so the first factor goe

s to the hundredths place.

2 answers:

Andrej [43]3 years ago

6 0

Answer:

whats the problem

Step-by-step explanation:

inn [45]3 years ago

5 0

Yejhdbdhdjbdbdbxbbxbd

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eli worked on a part time job in summer for 6 days. he worked 4 hours on each of the 6 days. he was paid a total of 300 for his

galina1969 [7]

Answer:

$12.50 per hour

Step-by-step explanation:

4 0

4 years ago

If each quadrilateral below is a parallelogram, find the missing measures.

prisoha [69]

Step-by-step explanation:

We will use parallelogram properties to answer our given problems.

(1) Since we know that opposite sides of parallelogram are congruent, therefore measure of side MN and side KN will be equal to the measure of their opposite sides.

LM=KN and KL=MN

Upon substituting our given values we will get,

45=KN and 31=MN

Property: The opposite angles of parallelogram are congruent and consecutive angles are supplementary.

We have been given $m\angle N=119^{o}$ , therefore $m\angle L=119^{o}$ .

We will find measure of angle K by using supplementary angles.

$m\angle N+m\angle M=180^{o}$

$119^{o}+m\angle M=180^{o}$

$m\angle M=(180-119)^{o}$

$m\angle M=61^{o}$

By opposite angles of parallelogram $m\angle K=61^{o}$ .

(2) Opposite sides of parallelogram are equal. Therefore, CF=DE and FE=CD.

Upon substituting our given values we will get,

CF=10 and FE=15.

Property: Diagonals of parallelogram bisect each other.

So CE will be 2 times CG and GD will be half the length of FD.

$CE=2\times 7=14$

$GD=\frac{1}{2}\times 22=11$

(3) Property: Opposite sides of parallelogram are congruent.

$SR=PQ$ and $QR=PS$

Upon substituting our given values we will get,

$SR=24$ and $QR=19$

Property: Diagonals of parallelogram bisect each other.

So SQ will be 2 times TQ and PT will be half the length of PR.

$SQ=2\times 10=20$

$PT=\frac{1}{2}\times 42=21$

Property: The opposite angles of parallelogram are congruent and consecutive angles are supplementary.

$m\angle PQR=106^{o}$

$m\angle PQS=m\angle QSR$ Alternate interior angles.

$m\angle PQS=49^{o}$

$m\angle QRS=m\angle QPS$ Opposite angles of parallelogram.

$m\angle PQR+m\angle QPS=180^{o}$

$106^{o}+m\angle QPS=180^{o}$

$m\angle QPS=180^{o}-106^{o}$

$m\angle QPS=74^{o}$

Therefore, measure of angle QRS will 74 degrees.

$m\angle PRS=m\angle QPR$ Alternate interior angles.

$35^{o}=m\angle QPR$

$m\angle RPS=74^{o}-m\angle QPR$

$m\angle RPS=74^{o}-35^{o}$

$m\angle RPS=39^{o}$

Now let us find measure of angle PSQ.

$m\angle PSQ=m\angle PQR-m\angle QSR$

$m\angle PSQ=106^{o}-49^{o}$

$m\angle PSQ=57^{o}$

The image is not clear, so I am unable to answer the last two problems.

5 0

3 years ago

Read 2 more answers

Find (6) x (-3) <br><br> What is the answer to this?

Amanda [17]

Answer:

Multiply 6 by −3.

−18

Step-by-step explanation:

Hope it is helpful.....

4 0

3 years ago

Read 2 more answers

There are 15 boys and 21 girls in a class. Write the simplified ratio of boys to students in three different ways.

gladu [14]

There are 6 less boys then girls
there are 6 more girls then boys
there are 15 boys compared to 21 girls

4 0

3 years ago

Read 2 more answers

Daily high temperatures in St. Louis for the last week were as follows: 95, 92, 93, 92, 95, 90, 90 (yesterday). a) The

hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as follows:

95, 92, 93, 92, 95, 90, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the 2-day moving average

Solution:

a)

- The set of 3 day moving average is as follows:

4. (95 + 92 + 93) ÷ 3 = 93.33⁰C

5. (92 + 93 + 92) ÷ 3 = 92.33⁰C

6. (93 + 92 + 95) ÷ 3 = 93.33⁰C

7. (92 + 95 + 90) ÷ 3 = 92.33⁰C

8. (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3. (95 + 92) ÷ 2 = 93.5⁰C

4. (95 + 93) ÷ 2 = 92.5⁰C

5. (93 + 92) ÷ 2 = 92.5⁰C

6. (92 + 95) ÷ 2 = 93.5⁰C

7. (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

Error Error^2

3. 93.5⁰C 0.5 0.25

4. 92.5⁰C 0.5 0.25

5. 92.5⁰C 2.5 6.25

6. 93.5⁰C 3.5 12.25

7. 92.5⁰C 2.5 6.25

8. 90⁰C

- The mean absolute deviation as follows:

MAD = Sum of all errors / 5

MAD = (0.5+0.5+2.5+3.5+2.5) / 5

MAD = 1.9

d)

- The mean squared error deviation as follows:

MSE = Sum of all error^2 / 5

MSE = (0.25+0.25+6.25+12.25+6.25) / 5

MSE = 5.05

4 0

3 years ago