Let the original length of the square be x cm.
(x+5) X (x-2) = 60
Or, x^2-2x+5x-10-60 = 0
Or, x^2+3x-70=0
Or, x^2+10x-7x-70=0
Or, x(x+10)-7(x+10)=0
Or, (x-7)(x+10)=0
Therefore, x=7 or x=-10 (rejected as the length cannot be negative)
Ans: Area of the square=l^2=7^2=49 square meters.
Answer: OPTION D.
Step-by-step explanation:
You can observe in the graph that represents f(x) that this function intersects the x-axis at the point (1,0). Then:

We know that a function intersects the x-axis when
.
We can observe the table that represents the function g(x). When the value of "y" is 0 (
), the value of "x" is -1 (
). Therefore, the x-intercept of f(x) is greater that the x-intercept of g(x).
You can observe in the graph that represents f(x) that this function intersects the y-axis at the point (0,-1). Then:

We know that a function intersects the y-axis when
. In the table that represents the function g(x), we can see that, when the value of "x" is 0 (
), the value of "y" is 1 (
). Therefore, the y-intercept of g(x) is greater that the y-intercept of f(x).
Answer:
Step-by-step explanation:
<u>As per question we have:</u>
- 2(l + w) = 414 ⇒ l + w = 207
- l = 5w - 39
<u>Solve it for l by substitution:</u>
- 5w - 39 + w = 207
- 6w = 207 + 39
- 6w = 246
- w = 246/6
- w = 41
<u>Find l:</u>
Check the picture below.
make sure your calculator is in Degree mode.
but will run you about 36.8698976458° and 53.13010235415598°.
Answer:
X=3 x=2
Step-by-step explanation: