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Ghella [55]
3 years ago
13

Find the standard form of the equation of the parabola with a focus at (-8, 0) and a directrix at x = 8

Mathematics
1 answer:
il63 [147K]3 years ago
8 0
The best thing to do when finding conic equations from the focus and directrix is to sketch a little graph. When you do this, you can easily identify the vertex right in the middle and can determine if the parabola is vertical or horizontal since it must wrap around the focus. This way you know whether the x or the y is squared. When you sketch the focus and directrix, you will see the vertex is at (0,0) and the parabola is sideways, so the y is squared. now remember your formula is y^2=4px where p is the distance from the vertex to the focus, or you could write x=1/(4p)y^2. Now from 0 to -8 is -8 so that means 4p=-32. This gives you y^2=-32x or x=-1/32y^2. Thsi type of question will also be on your module exam and then the final exam so be sure to practice some:)
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simplify the following expression: (x+7/4x) + (5/x-8) I also attached a photo of the problem if you get confused on how I typed
Gnoma [55]

Answer:

\frac{x^{2}  + 19x - 56}{4 {x}^{2}   - 32x}

Step-by-step explanation:

Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

Lastly, expand the denominator.

\frac{x + 7}{4x}  +  \frac{5}{x - 8}

=  \frac{(x + 7)(x - 8)}{4x(x - 8)}  +  \frac{5(4x)}{4x(x - 8)}

=  \frac{x(x) + x( - 8) + 7(x) + 7( - 8) + 20x}{4x(x - 8)}

=  \frac{ {x}^{2} - 8x + 7x - 56 + 20x }{4x(x - 8)}

=  \frac{ {x}^{2}  + 19x - 56}{4x(x - 8)}

=  \frac{ {x}^{2}  + 19x - 56}{4 {x}^{2}  -  32x}

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So put value of x and find f(x) and fill the input-output table.

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