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Ghella [55]
3 years ago
13

Find the standard form of the equation of the parabola with a focus at (-8, 0) and a directrix at x = 8

Mathematics
1 answer:
il63 [147K]3 years ago
8 0
The best thing to do when finding conic equations from the focus and directrix is to sketch a little graph. When you do this, you can easily identify the vertex right in the middle and can determine if the parabola is vertical or horizontal since it must wrap around the focus. This way you know whether the x or the y is squared. When you sketch the focus and directrix, you will see the vertex is at (0,0) and the parabola is sideways, so the y is squared. now remember your formula is y^2=4px where p is the distance from the vertex to the focus, or you could write x=1/(4p)y^2. Now from 0 to -8 is -8 so that means 4p=-32. This gives you y^2=-32x or x=-1/32y^2. Thsi type of question will also be on your module exam and then the final exam so be sure to practice some:)
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Since you need the vertex, and knowing the vertex will tell you the axis of symmetry, it is convenient to put the equation in vertex form.
.. -x^2 -4x +1
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Answer:

A. 2.2

Step-by-step explanation:

The average rate of change between 2 x values is the total change of the y values (output values) divided by the change in the x values.Slope is special situation of that.

point 1 (x₁,y₁) → ( 2,7.5)

point 2 (x₂,y₂) → ( 18,42.5)

slope = 42.5 -7.5/18-2 =35 / 16 = 2.1875 ≈ 2.2

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