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Morgarella [4.7K]
3 years ago
14

The work of a student to solve the equation 3(3y − 8) = 10 + 3y is shown below:

Mathematics
1 answer:
kirill115 [55]3 years ago
3 0
Step 2 9y - 24 = 10 + 3y because 3 times 3y its not 6y nor is 3 times 8 equal to 5
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Firlakuza [10]
You would turn the 15% into a decimal which is .15 then multiply .15 by 4.25. After multiplying those together add 4.25 to the answer.
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What is a interior angles in geometry
Inga [223]

Answer:

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Step-by-step explanation:

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3 years ago
Add and Subtract Rational Expressions with a Common Denominator
Sladkaya [172]

Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

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2 years ago
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soldier1979 [14.2K]

Answer:

1.83333333333

Step-by-step explanation:

pls mark me brainliest

ok thanks :) :) :) :)

8 0
3 years ago
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vivado [14]

area=length*width

4*4=16

4+4+4+4=16

the perimeter is also 16

6 0
3 years ago
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