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n200080 [17]
3 years ago
7

Help I need help I don’t understand

Mathematics
1 answer:
goblinko [34]3 years ago
8 0

Answer:

a) 0

b)2

Step-by-step explanation:

a) Basically, the question is asking what the x value is when the y value is at 4, which would be 0.

b) Same thing here, but with the x value is when the y value is -2.

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What’s the correct answer ?
Leona [35]
The answer is a) 35


The steps:
180° - 95 ° = 85 °
180 ° - (85 ° + 60 °)=35 °
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3 years ago
What number is halfway between 28 and 82​
densk [106]

Answer:

the answer is 55

Step-by-step explanation:

(28+82)/2

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3 years ago
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Find 2p^2+3p-4 less 2p^2-3p+4
ad-work [718]
The answer that I got was 10
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3 years ago
The expression 53 ( 1 − x) gives the discounted price of a pair of shoes, where x is the percent of the discount written in deci
prisoha [69]

Answer: Option "A" is correct.

Step-by-step explanation:

Since we have given that

53(1-x) represents the discounted price of a pair of shoes , where x is the percent of the discount written in decimal form.

So,

(1-x) represents the percent of original price being paid as we know that if percentage is given in decimal form then to get the percent of  original price being paid  we subtract it from 1.

For example:

Suppose 20% is the percent of discount on market price then the selling price will be 80% of marked price.

In the above example, we subtract it from 100% to get the remaining price  he is receiving at.

If we have 0.2 as discount then the selling price will be 0.8 of marked price i.e. we get 0.8 which tells us the original price is being paid.


8 0
3 years ago
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Please help? Will make you the Brainliest!
Allushta [10]

Answer:

D. 19/2   D.-4/\sqrt{15}   D.cos^2x  look at explanation for last one

Step-by-step explanation:

1. Find the value of sec if cos delta  = 2/19

because sec is basically 1/cos, and since it's Quad I there's nothing weird, you can just flip the fraction

therefore it's  D. 19/2

2. Find the value of csc given cos delta = -1/4 and triangle is in third Quad

so cosine is adj over hypo: since the hypo can't ever be negative, the triangle must have a = -1 and c =4. to find bc use the c^2 = a^2 + b^2 to solve for b^2, and since it's third quad, b is negative, so b = -\sqrt{15}2. NOw that you know all three sides, finding csc is ez. So csc is hypo over opposite bc its opposite of sine, so therefore csc delta = -4/\sqrt{15}

3. simplify sin^2qcot^2

ok, so if cot is opposite of tan, and tan is sine over cos, cot must be cos over sine :D! SO cot^2 = \frac{cos^2x }{sin^{2}x}. multiply that by sin^2 and the sines will cancel, leaving you with just cos^2x! sorry, I used x insead of q out of habit... oops!

4. determine the quad if sine delta = -1/4

sine is opposite over hypo, and as mentioned before, hypo can't equal to negative, so the opposite side must be negative. therefore, the triangle must lie in quad III or quad IV

ahem, these are your answers, idk why is it all D lol, I hope this helped. sorry this was so long!

8 0
3 years ago
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