All categories

3 years ago

Can someone help me with this please

Mathematics

1 answer:

erastova [34]3 years ago

8 0

Not positively sure but I believe it goes like this

Answer: 9x+26+5x=180

14x+26=180

180-26=14x

14x=154

X=15

You might be interested in

PLEASE HELP ASAP!!! 70 POINTS AND BRAINLIEST FOR FASTEST AND BEST ANSWER!!!

Novay_Z [31]

Answer:

The IQR is the best measurement of spread for games and movies.

Step-by-step explanation:

Because both seem to have outliers, we want to use IQR instead of standard deviation to determine the spread of data.

8 0

3 years ago

Read 2 more answers

I don’t know how to answer my this math question, it’s easy so please help

Fofino [41]

which one ?

the bottom or the top or is this a trick

7 0

3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago

What is the result when the number is 72 is decreased by 44%. Round your answer to the nearest tenth?

Sonbull [250]

The answer is 164 I believe

4 0

3 years ago

Find the percent of change. 68 to 42.5

ohaa [14]

Your answer would be 176.25%

7 0

3 years ago

Read 2 more answers