All categories

3 years ago

Select all the expressions that are equal to 9/41

Mathematics

1 answer:

Dahasolnce [82]3 years ago

5 0

Answer:

yaa first u know that

Step-by-step explanation:

tan g=p/b ok then tang=40/9 okay

You might be interested in

Convert 40 ounces into pounds. Round your answer to the nearest tenth.

alex41 [277]

Answer:

Step-by-step explanation:

7 0

2 years ago

Spencer sampled 50 students of a private school who were questioned about their scores in Mathematics. Spencer wants to test the

pickupchik [31]

Answer:

C) 3.03

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 50

The Mean of the population (μ) = 62

The standard deviation of the Population (σ) = 7

Mean of the sample(x⁻) = 65

Z-score

$Z= \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

Step(ii):-

$Z= \frac{65 -62}{\frac{7}{\sqrt{50} } }$

Z = 3.03

Final answer:-

The Z-score = 3.03

6 0

4 years ago

Which of the following statements is false? A rational number cannot be an irrational number. An irrational number is always a r

svp [43]

An irrational number is always a real number - false

A rational number cannot be an irrational number. - true, it is rational by definition

An integer will always be a rational number - true, integers are rational

A natural number cannot be an integer. - it can, for example 42

7 0

4 years ago

3. A model rocket is launched from the ground with an initial velocity of 352 ft/sec.

Hoochie [10]

Answer:

e. It will take 11 seconds to reach the maximum height of 1,936 feet.

f. It will take 22 seconds to return to the earth.

Step-by-step explanation:

Given:

Initial velocity $v_0$ = 352 ft/sec

Solving for question e.

To find the time required to reach the maximum height we will use the formula,

$h(t) = -16t^2+v_0t+h_0$ ,

where $v_0$ is the starting velocity

$h_0$ is the initial height.

Using the velocity and starting height from our problem we have,

$h(t) = -16t^2+352t+0$ ,

The path of this rocket will be a downward facing parabola, so there will be a maximum.

This maximum will be at the vertex of the graph.

To find the vertex we start out with $x= \frac{-b}{2a}$ which in our case is,

$x=\frac{-352}{2(-16)}=\frac{-352}{-32}= 11$

So, It will take 11 seconds for the rocket to reach its maximum height.

We will find maximum height using the formula by substituting value of t we get,

$h(11)=-16(11^2)+352(11)+0\\h(11) = -16 \times121+ 352 \times 11 = -1936+3872= 1936 \ ft$

Hence the maximum height will be $1936 \ ft$

Now Solving for question f.

To find the time required for rocket to reach earth.

We will set our formula to 0 to find the time.

$0= -16t^2+352t+0\\-16t(t-22)=0$

Using the zero product property, we know that either -16t = 0 or t - 22 = 0. When -16t = 0 is at t = 0, when the rocket is launched. t - 22 = 0 gives us an answer of t = 22.

So the rocket reaches the Earth again at 22 seconds.

8 0

3 years ago

Please help for brainliest.

SVETLANKA909090 [29]

Answer:

Company d

apperantly i gotta write 20 letters

3 0

3 years ago