Answer:
see below
Step-by-step explanation:
prove: sin²x cos²y - cos²x sin²y ≡ sin²x - sin²y
we notice that the Right side only has sin² functions, hence we can start by trying to remove the cos² functions from the Left side.
Recall the identity: sin²α + cos²α = 1 , can be rearranged to give us:
cos²α = 1 - sin²a.
If we apply this to the left side of our equation, then
cos²y = 1-sin²y, and cos²x = 1-sin²x
Substituting these into the left side of the equation:
sin²x cos²y - cos²x sin²y
= sin²x (1-sin²y) - (1-sin²x ) sin²y
= sin²x - (sin²x sin²y) - sin²y + (sin²x sin²y)
= sin²x - sin²y
= Right Side of equation (Proven!)
Answer:
The standard form of this equation is -8x + 3y = -68
Step-by-step explanation:
In order to find this, first solve for the constant.
y = 8/3x - 68/3
-8/3x + y = -68/3
Now we multiply by 3 to get them all equal to integers.
-8x + 3y = -68
Answer:
x + √x - 6
Step-by-step explanation:
Multiply out (√x-2)(√x+3) using the FOIL method:
Multiply the First terms: x
Multiply the Outside terms: 3√x
Multiply the Inside terms: -2√x
Multiply the Last terms: -6
Now combine these results. We get:
x + √x - 6
