If X-1 = 8, what justifies x - 1 = 16?
1 answer:
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Answer:
0.0032
Step-by-step explanation:
We need to compute by the help of third-degree Taylor polynomial that is expanded around at x = 0.
Given :
< e < 3
Therefore, the Taylor's Error Bound formula is given by :
, where
Therefore, |Error| ≤ 0.0032
The first step for solving this expression is to write the division as a fraction.
x +
× x
Calculate the product.
Remember that if a term doesn't have an exponent,, it is considered that the exponent for that term is 1. This changes the expression to the following:
Now multiply the terms with the same base by adding their exponents.
Finally,, add the numbers together to get your final answer.
x +
Let me know if you have any further questions.
:)
x +
Calculate the product.
Remember that if a term doesn't have an exponent,, it is considered that the exponent for that term is 1. This changes the expression to the following:
Now multiply the terms with the same base by adding their exponents.
Finally,, add the numbers together to get your final answer.
x +
Let me know if you have any further questions.
:)