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2 years ago

15

When performing tests involving two or more populations it is important to specify which population is population 1 and which is

population 2.
a. True
b. False

1 answer:

iris [78.8K]2 years ago

3 0

Answer:

a. True

Explain:

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Find (g/f)(x) for the given functions: f(x) = 5/x and g(x) = 3 + x/5

Vesna [10]

Step-by-step explanation:

just substitute the value of g(X) and f(X)

8 0

3 years ago

Corinna has $80. She wants to buy a $256 plane ticket. She will save up her earnings from working at the museum where she earns

Gnesinka [82]

Answer:8

Step-by-step explanation:

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

7 0

2 years ago

six times the sum of a number and 3 is 12 less than 12 times the number .Write and solve an equation to fine the number

Aloiza [94]

6 (x+3)=12x-12

6x+18=12x-12

6x-12x=-18-12

-6x=-30

x=5

4 0

3 years ago

The circles are identical. What is the circumference of each circle? Circle 1: radius of 2x; Circle 2: diameter of 2x+3. A. 3/2

Delicious77 [7]

Answer:

C=6π

Step-by-step explanation:

It is given that, two circles are identical. The radius of first circle is 2x and the diameter of other circle is 2x+3.

If identical, it means that the radius of both circles are same i.e.

$2x=\dfrac{2x+3}{2}\ \ (\because\ r=\dfrac{D}{2}, d=\text{diameter})\\\\4x=2x+3\\\\2x=3\\\\x=1.5$

Radius of both circles is 2(1.5)=3

The circumference of a circle is given by :

$C=2\pi r\\\\C=2\pi (3)\\\\C=6\pi$

So, the circumference of each circle is 6π.

7 0

3 years ago