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zysi [14]
3 years ago
9

What is the median value of the data set shown on the line plot?

Mathematics
2 answers:
VLD [36.1K]3 years ago
3 0
I'm more visual, but if you're not, and this confuses you, ask me, and I'll explain it.

Dovator [93]3 years ago
3 0

Answer provided in image attached.

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If the first term of the series is 30 and the 14th term is 95, what is the sum of all the terms of the series?
RideAnS [48]

Answer:

D)  S_{14} = 875.

Step-by-step explanation:

Given  : If the first term of the series is 30 and the 14th term is 95,

To find : what is the sum of all the terms of the series.

Solution : We have given

First term = 30 .

14 th term = 95.

Sum of all term = S_{n} =\frac{n(first\ term +\ last\ term)}{2}.

Here, n = 14.

 S_{14} =\frac{14(30 +95)}{2}.

 S_{14} =\frac{14(125)}{2}.

 S_{14} =\frac{1750}{2}.

 S_{14} = 875.

Therefore, D)  S_{14} = 875.

7 0
4 years ago
Read 2 more answers
(a) (4,4) is a point on a locus whose equation is y2 = kx. Show that (16,8) is another point on the locus.
Vlad [161]

Step-by-step explanation:

plug the coordinate points into the equations and solve for the remaining variable.

b) (2,3) - 5(2) + b(3) = 16

10 + 3b = 16. 3b= 6. b = 2

(0,8) - 5(0) + 2(8) = 16. 0+ 16 = 16. ☆

a) (4,4) assume based on results you meant y squared. (y^2)

(4)^2 = 4k. 16 = 4k. k = 4

(8)^2 = 4(16). 64 = 64. ☆

6 0
3 years ago
Read 2 more answers
I don't get any of this, I am so overly confused
Colt1911 [192]
There was one I couldn't solve. Sorry about that.

4 0
4 years ago
Factor the expression by finding the GCF. 16m2 − 12m
ziro4ka [17]

Answer:

4m(4m-3)

Step-by-step explanation:

16m^2 − 12m

16 m^2 = 2*2*2*2*m*m

12m = 2*2*3*m

The greatest factor for 16m^2 and 12m is 2*2*m  or 4m

Factor out 4m

16 m^2 = 2*2*2*2*m*m = 4m(2*2m)=4m(4m)

12m = 2*2*3*m = 4m(3)

Factoring out 4m

16m^2 − 12m

4m(4m-3)

3 0
3 years ago
Read 2 more answers
Find the Average Rate of Change between the values of [-5, 0].
lawyer [7]

Answer:

1?

Step-by-step explanation:

am not sure sorry if am wrong

8 0
4 years ago
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