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svet-max [94.6K]
3 years ago
14

Can some one hlep me with this

Mathematics
2 answers:
lianna [129]3 years ago
6 0

Answer:

IHBKNONOO JG67HJUBDIJGUXJ FJNIGU9JUFGKXJVNGD

Step-by-step explanation:

Alinara [238K]3 years ago
5 0

Answer:

hhgfcvbn

Step-by-step explanation:

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100 POINTS AND BRAINLIYEST!!!
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See explanations below

Step-by-step explanation:

Chanel

(i) 90° counterclockwise and then dilation by a factor of 1/2

Trapezoid PQRS is given as :

P(6,-4) -------P'(4,6)

Q(2,-2)------Q'(2,2)

R(2,-6)-------R'(6,2)

S(6,-6)-------S'(6,6)

The transformation switches the position of (x,y) to and adds a -ve sign to the original y value

B. The new coordinates are : P'(4,6), Q'(2,2),R'(6,2) and S'(6,6)

The  rule for rotation 90° counterclockwise about the origin is (x,y)⇒(-y,x)

The rule for dilation with scale factor of 1/2 is (x,y)------(1/2x,1/2y)

P'(4,6) -----P''(2,3)

Q'(2,2)-----Q''(1,1)

R'(6,2)-----R''(3,1)

S'( 6,6)-----S''(3,3)

The dilation reduces the coordinates by 1/2

Preston

E. (i)Reflection over x-axis where the rule is : (x,y)----(x,-y)

(ii)Dilation by scale factor of 1/2 the rule is : (x,y)---(1/2x, 1/2y)

Applying reflection over x-axis rule;

P(6,-4) -----P'(6,4)

Q(2,-2)-----Q'(2,2)

R(2,-6)------R'(2,6)

S(6,-6)------S'(6,6)

The coordinates have changed in that a negative sign is added to the y-axis coordinate.

F. P'(6,4), Q'(2,2), R'(2,6) and S'(6,6)

G. Applying the dilation by scale factor of 1/2

P'(6,4)-------P''(3,2)

Q'(2,2)------Q''(1,1)

R'(2,6)------R''(1,3)

S'(6,6)------S''(3,3)

The coordinates of P'Q'R'S are divide by 2 to give coordinates of P''Q''R''S''

Comparing the answers to the final figure given

K(3,2)

L(1,1)

M(1,3)

N(3,3)

Preston is correct because his sequence proves trapezoid PQRS is similar to trapezoid KLMN.

Learn More

Reflection and dilation :brainly.com/question/13408902

Keywords :trapezoid, maps, rotate, counterclockwise, dilate,reflect,scale factor,shape, coordinate

#LearnwithBrainly

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A 3.5 ft by 5.5 ft mirror is placed in a wooden frame. What is the area of the frame
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What problem or problems could we potentially run into if we use graphs to find the exact roots
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The possible problems  of using graphs to find roots are:

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<h3>How to find the roots of a quadratic function with a graph?</h3>

First, the roots of a quadratic function are the values of x such that:

a*x^2 + b*x + c = 0

To find the roots using a graph, we need to see at which values of x does the graph of the parabola intercepts the horizontal axis.

<h3>What are the possible problems with this method?</h3>

There are two, the first one is having irrational roots, in that case, an analytical or numerical approach will give us a better estimation of the roots. Finding irrational values by looking at the intercepts of the graph can be really hard, so in these cases using the graph to find the roots is not the best option.

The other problem is if we <u>don't have real roots</u>, this means that the graph never does intercept the horizontal axis. In these cases, we have complex roots, that only can be obtained if we solve the problem analytically.

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