I think so it is between 51~56%
3x + 1y = ¹/₃ ⇒ 9x + 3y = 1
2x - 3y = 2²/₃ ⇒ 2x - 3y = 2²/₃
11x = 3²/₃
11 11
x = ¹/₃
3x + y = ¹/₃
3(¹/₃) + y = ¹/₃
1 + y = ¹/₃
- 1 - 1
y = ⁻²/₃
(x, y) = (¹/₃, ⁻²/₃)
180-48.2-75=56.8 thank you
We have 5% and 6.5% acetic acid solutions and we need 200 ml of 6% acetic acid.
Set up two equations:
f means 5% and s means 6.5%
A) f + s = 200
B) .05f + .065s = (.06 * 200)
Multiplying equation A by -.05
A) -.05f -.05s = -10
B) .05f + .065s = 12 then adding both equations:
.015s = 2
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we need 133.33</span> ml of 6.5% acetic acid and
66.67 ml of 5% acetic acid solution.
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Source:
http://www.1728.org/mixture.htm