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inysia [295]
2 years ago
5

The sum of 4 and y divided by 5 equal to 9. Find the value of y.​

Mathematics
1 answer:
Sophie [7]2 years ago
6 0

Answer:

y = 41

Step-by-step explanation:

When you add 41 and 4, you would get 45.

When you divide by 5, it will be equal to 9:

45 ÷ 5 = 9

---------------------------------------------------------------------------------------------------------------

Have a great summer :)

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Answer:

\frac{7}{40}

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The distribution of heights of adult American men is approximately Normal with mean 69 inches and standard deviation 2.5 inches.
nalin [4]

Answer:

option C 13.5%

Step-by-step explanation:

As the heights of adults is normally distributed with mean=69 and standard deviation=2.5 so, the percent of men that are between 64 and 66.5 inches tall can be calculated as

P(64<X<66.5)=P[ (64-69)/2.5<(X-μ)/σ<(66.5-69)/2.5]

P(64<X<66.5)=P(-2<Z<-1)

P(64<X<66.5)=P(-2<Z<0)-P(-1<Z<0)

P(64<X<66.5)=0.4772-0.3413=0.1359

Thus, the percent of men are between 64 and 66.5 inches tall is 13.59%.

If we round the resultant quantity then it will be rounded to 13.6% but considering the given options, option C is most appropriate.

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3 years ago
Complete the equation of the line through (-6,-5) (−4,−4) PLZ HELP !!!
bogdanovich [222]

Answer: y=1/2x−2

Step-by-step explanation:

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3 years ago
The low temperature for 5 days were negative 5゚ negative 7゚ negative 2゚ degrees and negative 3゚ what was the average low tempera
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(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
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