3 years ago

PLSSS SOMEONE HELP MEEE 1: a, c 2: a,c

Mathematics

1 answer:

Savatey [412]3 years ago

4 0

Answer:

Step-by-step explanation:

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Suppose the total area is represented by the equation x^2+14x+24. If the area 1 is x^2 square units and area IV is 24 units, wha

Nutka1998 [239]

Answer:

See Explanation

Step-by-step explanation:

Given

$Total = x^2 + 14x + 24$

$Area\ I = x^2$

$Area\ IV = 24$

Required

True about area II and III

The question is incomplete; so, I will answer using general knowledge.

If the total area is:

$Total = x^2 + 14x + 24$

And there are 4 areas, then;

$Total = Area\ I + Area\ II + Area\ III + Area\ IV$

Rewrite as:

$Total = Area\ I + Area\ IV+ Area\ II + Area\ III$

This gives:

$x^2 + 14x + 24 = x^2 + 24+ Area\ II + Area\ III$

Collect like terms

$x^2 -x^2 + 14x + 24 -24= Area\ II + Area\ III$

$14x = Area\ II + Area\ III$

Rewrite as:

$Area\ II + Area\ III = 14x$

<em>So, the sum of areas III and IV must be 14x</em>

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