The least power of 2 that exceeds 25 is
, so we have
- - -
The least integer
that satisfies this inequality would clearly be
.
True because the distance should have no beginning or end
Answer:
(E) 27
Step-by-step explanation:
Let the 5 digit palindrome be PQRQP
Since each digit is chosen from 1,2,3 therefore
P can either be 1,2 or 3 which gives us 3 options.
Q can also either be 1,2 or 3 which gives us 3 options
R can either be 1,2 or 3 which also gives us 3 options
So we have 3^3 = 3*3*3
= 27
This means 27 palindromes are possible if they are formed using one or more of the digits, 1, 2, 3.
She purchased 4 children’s tickets. To solve you find out that she buys 3 adult tickets worth $27. Then add $4 until $43.
