Answer:
d
Step-by-step explanation:
if you tried to do the d you would end up with this
/_)
If the circle has the same center as the diagonals of a square and the radius of the circle is smaller than 1/2 the diagonal of the square but larger than 1/2 the length of the side of a square, then there are 8 points of intersection -- 2 at each corner of the square.
If the radius of the circle is smaller than 1/2 the side length of the square and the center is as described above, there are no points of intersection.
If the circle is located outside the square it can have 1 tangent point or 2 intersection points depending on the location conditions of the circle in relation to the square.
Answer:
8 1/4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
Point (-1, -3.75)
Point (-1, 4.5)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute in points [Distance Formula]:

- [√Radical] (Parenthesis) Subtract:

- [√Radical] Evaluate exponents:

- [√Radical] Add:

- [√Radical] Evaluate:

Let x,x+2,x+4,x+6 be 4 consecutive no then,
sum of first 3 no=4x+12
According to condition,
20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd
5(x+6)-20=4+(sum of first 3 no)
5(x+6)-20=4+(4x+12)
5(x+6)-20=4x+16
5x+30-20=4x+16
5x+10=4x+16
5x-4x=16-10
x=6
So,
1st no=x=6
2nd no=x+2=8
3rd no=x+4=6+4=10
4th no=x+6=6+6=12