Answer:
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No I do not think that 12/60 and 16/40 are equivalent because onec you reduce both of the fractions it does not equal.
Answer:
Step-by-step explanation:
4x - 25 = 75° (opposite angles)
4x= 75+25
4x= 100
x= 100/4= 25°
Answer:
Choice A) .
Step-by-step explanation:
What are the changes that would bring to ?
- Translate to the left by unit, and
- Stretch vertically (by a factor greater than .)
. The choices of listed here are related to :
- Choice A) ;
- Choice B) ;
- Choice C) ;
- Choice D) .
The expression in the braces (for example as in ) is the independent variable.
To shift a function on a cartesian plane to the left by units, add to its independent variable. Think about how , which is to the left of , will yield the same function value.
Conversely, to shift a function on a cartesian plane to the right by units, subtract from its independent variable.
For example, is unit to the left of . Conversely, is unit to the right of . The new function is to the left of . Meaning that should should add to (rather than subtract from) the independent variable of . That rules out choice B) and D).
- Multiplying a function by a number that is greater than one will stretch its graph vertically.
- Multiplying a function by a number that is between zero and one will compress its graph vertically.
- Multiplying a function by a number that is between and zero will flip its graph about the -axis. Doing so will also compress the graph vertically.
- Multiplying a function by a number that is less than will flip its graph about the -axis. Doing so will also stretch the graph vertically.
The graph of is stretched vertically. However, similarly to the graph of this graph , the graph of increases as increases. In other words, the graph of isn't flipped about the -axis. should have been multiplied by a number that is greater than one. That rules out choice C) and D).
Overall, only choice A) meets the requirements.
Since the plot in the question also came with a couple of gridlines, see if the points 's that are on the graph of fit into the expression .
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
How to determine average velocity and instantaneous velocity?
Average velocity is defined as the body's overall displacement divided by its time of motion. While instantaneous velocity is defined as a body's speed at a certain instant in time, or its displacement at that instant. When the velocity is constant, average and instantaneous velocities will equalize at just one condition.
The definition of instantaneous velocity is the rate of change of position over a relatively brief time period (almost zero). Simply said, the speed of an object at that precise moment. The definition of instantaneous velocity is "The velocity of an item in motion at a certain point in time." The instantaneous velocity of an object may be equal to its standard velocity if it has uniform velocity.
Mathematically, average velocity = [s(t₂) - s(t₁)]/[t₂ - t₁]
Instantaneous velocity at time, t is = (ds/dt) at time = t
Given, the displacement for the particle is given by s = 3t² - 4t + 5
Time interval, t₁ = 5s and t₂ = 3s;
Using formula in literature, average velocity of the particle in the time interval between 3s and 5s is:
Average velocity = (s(5) - s(3))/(5 - 3) = (60 - 20)/2 = 20 ms⁻¹
Instantaneous velocity at t = 4 is ds/dt at that time-frame:
Now, v = ds/dt = 6t -4
Now, v(4) = 6(4) - 4 = 20 ms⁻¹
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
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