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e-lub [12.9K]
3 years ago
11

I'm taking a test rn does anyone know this question

Mathematics
2 answers:
Anna007 [38]3 years ago
6 0

Answer:

9 ft.

Step-by-step explanation:

lara31 [8.8K]3 years ago
5 0

Answer:Let the base of the 15ft long ladder be placed x ft away from the wall so that it exactly reaches the top of a 12- foot tall wall.

By Pythagorean theorem

12

2

+

x

2

=

15

2

⇒

x

2

=

15

2

−

12

2

=

81

⇒

x

=

√

81

=

9

ft

Step-by-step explanation:

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Please help me look at the attached picture
Lady bird [3.3K]

Answer:

Q(-10) = 299

Step-by-step explanation:

Q(x) = 3x^{2} - 1Q(-10) = 3(-10)^{2} - 1

Q(-10) = 3(100) - 1  (-10 to the second power is 100 (negative times a negative equals a positive)

Q(-10) = 300 - 1  3 times 100 equal 300

Q(-10) = 299

5 0
3 years ago
A researcher gathers a sample of n=89 people to try a new
muminat

Answer:

24

Step-by-step explanation:

+#;$;_;_:;+$hshshsbbsns

5 0
3 years ago
Can someone answer number 11?
Anna71 [15]

Answer:

Step-by-step explanation:

To be rational means to be able to express the result as the ratio of two whole numbers.

a) 4/7 + (-1/3) = 12/21 - 7/21 = 5/21 so rational

b) √(4) • 2/5 = ±2 • 2/5 = ±4/5 so both solutions are rational

5 0
3 years ago
Read 2 more answers
Solve this system of equations using substitution:
irina [24]
The substitution method means you replace the variable in one equation with the other equation, so your new equation is x+4x-8=10. Add 10 to both sides to get 5x=18. Divide both sides by 5 to get x=3.6. This is a weird equation, but then to get y, work backwords. 3.6 times 2=7.2. 7.2-4=3.2 y=3.2. Finally to finish checking solve the equation as normal. 3.6+6.4=10. I hope this helped! Please give brainliest!
Your final answer is x=3.6 y=3.2
3 0
3 years ago
PLEASE HELP MEEEE HURRRY!!! :)
sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}  First, I swapped the first and third rows.

\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}  Leading coefficient of row 2 canceled.  

\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}  The start value of row 3 was canceled.

\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}       Matrix rows 2 and 3 were swapped.

\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}      Leading coefficient in row 3 was canceled.

\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}

The positioning of the zeros indicated that there was no solution!

<u><em>Hope that helps!</em></u>

6 0
3 years ago
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