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pshichka [43]
3 years ago
12

11) Help pls I have the answer I just need to show the work.

Mathematics
1 answer:
spayn [35]3 years ago
4 0
True.
The Pythagorean theorem is a^2 + b^2 = c^2 where a^2 and b^2 are the two legs of the triangle (two sides connected by the right angle) and c is the hypotenuse (longest side, opposite the right angle).

To solve using the Pythagorean theorem, plug in sides AC and CB into a and b, then solve for c.

23^2 + 31^2 = c^2
529 + 961 = c^2
c^2 = 1490
c = √1490 = 38.601

I hope this helps!
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Assume that Brad makes an initial investment of $2,000. Use your formula to find the final balance of the savings account after
svetlana [45]

Answer:

The formula is 2000 x (1 + Rate/100)^15

5 0
3 years ago
C=5/9(F-32) solve for F
mina [271]
<span>F= 9/5 C + 32
      or
</span><span>F= 9/5(C+32)
</span>                          Hoped this helped:)
7 0
3 years ago
Find the total number of outcomes, rolling a number cube and tossing<br> two coins
Tcecarenko [31]

A number cube has 6 different numbers.

A coin can have 2 outcomes ( heads or tails.)

Total out comes = 6 x 2 x 2 = 24

5 0
3 years ago
Class A has 15 pupils and class B has 29 pupils.
Vaselesa [24]

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:

Mean score of A = (sum of all scores) / 15

55 =  (sum of all scores) / 15

sum of all scores in A = 825

The mean score for both classes is 76. Hence:

[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes

[825 + (sum of all scores in B)]/(15 + 29) = 76

sum of all scores in B = 2519

Mean score of B = (2519) / 29 = 86.86

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

Find out more on equation at: brainly.com/question/13763238

#SPJ1

6 0
2 years ago
NEED HELP ASAP.....At the 2012 Summer Olympic Games in London, in the Men's Shot Put qualifying round, the distances ranged from
jeka57 [31]

Answer:

About 6 athletes.

Step-by-step explanation:

We are concerned only with the percent of athletes that are above one standard deviation.

Between one standard deviation and two standard deviations, there is 13.6% of the athletes.

From 2 to 3, there is 2.1%. Above 3, there is 0.2%.

The sum of those percentages is 15.9% of 40 = 0.159 · 40 = 6.36 or about 6 athletes.

Hope this helps.

6 0
4 years ago
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