Answer:C) PEAP(Protected Extensible Authentication Protocol)
Explanation: PEAP(Protected Extensible Authentication Protocol) is the protocol that is used in point-to-point network connection and wireless network connection.It is the version of EAP(Extensible Authentication Protocol) with the advantage of protection to maintain the security.
Other options are incorrect because EAP-FAST is the EAP protocol with that has flexible authentication through secure tunneling, EAP-TLS is the EAP protocol with the transfer layer security and EAP is used for the expansion of authentication method for the network between internet and computer system.Thus, the correct option is option(c).
A program that is required to three (3) numbers. calculate and print their total is given below:
<h3>The Program</h3>
import java.util.Scanner;
public class SumAndAverage {
public static void main(String[ ] args) {
System.out.println("Enter three numbers - ");
// Accepting and finding sum of numbers.
int sum = 0;
Scanner sc = new Scanner(System.in);
for (int i = 0; i < 3; i++)
sum += sc.nextInt( );
// Printing sum and average.
System.out.println("Sum - " + sum);
System.out.println("Average - " + (sum / 3f));
}
}
The output would request three different numbers, then add them up, and display the output of the sum and then display or print their total
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3. 8.1
Looking at the functions "average", and "mystery" it's pretty obvious that "average" returns a double precision average of the value of an integer array. The function "mystery" returns an array of integers with each value in the array being the length of the string in the array of strings passed to "mystery" in the same ordinal position.
The main body of the code initializes an array of strings and then passes that array to "mystery" who's output is then passed into the function "average". Since the lengths of the words passed to "mystery" is 7, 5, 6, 10, 10, 8, 13, 6, 8, 8, the sum will be 81, so the average will be 81/10 = 8.1 which matches option "3".
Answer:
You could type<em> ipconfig www.cnn</em> in command promt.
Explanation:
