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2 years ago

Solve the inequality: a - 4 <10

Mathematics

1 answer:

harkovskaia [24]2 years ago

5 0

<h3>Answer: a < 14 (Choice B)</h3>

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Explanation:

Add 4 to both sides

a-4 < 10

a-4+4 < 10+4

a < 14

The reason why we add 4 to both sides is to undo the "minus 4" that's happening to the variable.

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Perfect Linear relationship between two or more independent variables is a violation of .... a. MLR.1 - Linearity in parameters

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Answer:

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Step-by-step explanation:

There is an assumption that nothing in the error term should correlate with the explanatory variable (x) of interest and outcome variable of (y). It does not allow any linear relation between two or more variables. If there is a relation between the variable it the the violation of this assumption.

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2 years ago

A survey of 125 randomly selected teens ages 13 to 16 found that 33 of them play soccer, 27 of them play basketball, 24 of them

iogann1982 [59]

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3 years ago

8. Lilly paid $19.16 for a 1kg apple basket. This amount includes a tax of 3%. What was the cost of the apple before tax?

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Answer:

19.75. The apples cost 19.75 before the tax.

Step-by-step explanation:

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2 years ago

markus wants to get no less than 90 percent on his next test. Let x represent his possible score on the test

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2 years ago

M is the midpoint of AN, A has coordinates

maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

Figure :-

$\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$} \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}$

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

$\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}$

On using this formula ,

$=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}$

8 0

2 years ago

Read 2 more answers