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Ksenya-84 [330]
3 years ago
10

Math Jakob only Jake answer.

Mathematics
1 answer:
Zanzabum3 years ago
4 0

Answer:

Jake is a college sophomore and a math and science prodigy. ... Morley Safer and producer Katy Textor did just that.

Step-by-step explanation:

Bruh.

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The student council hires a dj to play music at the school dance. They pay DJ Dan for 3.5 h at his hourly rate plus a 125$ setup
fiasKO [112]
3.5h + 125 = 405
3.5h = 280
hourly rate = 80 dollars
6 0
3 years ago
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If c(x) = 4x - 2 and d(x) = x + 5x what is (c×d)(x)?​
g100num [7]

Answer:

24x^2 - 12x

Step-by-step explanation:

C=4x -2

D=x + 5x

(4x - 2) * (x +5x)

4x^2 + 20x^2 - 2x - 10x

=24x^2 - 12x

5 0
2 years ago
If one-sixth of a number plus one-third returns two-thirds of that number What is the number
Solnce55 [7]

Answer:

x= \frac{2}{3}

Step-by-step explanation:

Let the number be x

Given

\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x

Required

Find x

\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x

Collect Like Terms

\frac{1}{6}x -  \frac{2}{3}x = - \frac{1}{3}

Take LCM

\frac{1 - 4}{6}x = \frac{-1}{3}

\frac{- 3}{6}x = \frac{-1}{3}

Multiply both sides by 6

6 * \frac{- 3}{6}x = \frac{-1}{3} * 6

-3x= -2

Divide both sides by -3

\frac{-3x}{-3}= \frac{-2}{-3}

x= \frac{2}{3}

Hence, the number is \frac{2}{3}

7 0
3 years ago
A(-3,2) B(5,-4) midpoint is (1,-1)
lesya [120]
CHECK:\\\\the\ midpoint\ AB:\left(\frac{-3+5}{2};\ \frac{2-4}{2}\right)=\left(\frac{2}{2};\ \frac{-2}{2}\right)=(1;-1)\\-------------------------------\\C(x;\ y)\\\\the\ midpoint\ AC:\left(\frac{-3+x}{2};\ \frac{2+y}{2}\right)\\\\B\ is\ the\ midpoint\ AC\ then:\\\\\frac{-3+x}{2}=5\ and\ \frac{2+y}{2}=-4\\\\-3+x=10\ and\ 2+y=-8\\\\x=10+3\ and\ y=-8-2\\\\x=13\ and\ y=-10\\\\Solution:C(13;-10).
7 0
3 years ago
PLZ HELP ASAP SOLID GEOMETRY WITH WORD PROBLEMS
Scilla [17]
The surface area of a cylinder is given by:
 A = 2 * pi * r * (r + h)
 Where,
 r: radio
 h: height
 Substituting values:
 A = 2 * pi * 3 * (3 + 8)
 Rewriting:
 A = 2 * pi * 3 * (11)
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A = 66pi square units
3 0
3 years ago
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