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2 years ago

Which statement is true about the regular octagon?

Mathematics

1 answer:

lidiya [134]2 years ago

4 0

Answer:

The answer is C

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Step-by-step explanation:

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How do I Divide. Write in simplest form

sladkih [1.3K]

Answer:

14/42

Step-by-step explanation:

Use the keep change flip strategy or butterfly multiply

6 0

2 years ago

A bakery offers a sale price of $3.45 for 4 muffins. What is the price per dozen?

Vlad [161]

Answer:

Cost of 4 muffins = $3.45

Cost of 12 muffins = (3 sets of x 4 muffins = 12)

Cost of 3 sets of muffins = $3.45 x3 = $10.35

Step-by-step explanation:

3 0

2 years ago

Geometry help please! Match the reasons with the statements.

SSSSS [86.1K]

Given:

∠PRS and ∠VUW are supplementary.

To prove:

Line TV || Line QS

Solution:

Step 1: Given

∠PRS and ∠VUW are supplementary.

Step 2: By the definition of supplementary angles

$m\angle {PRS}+m\angle {VUW}=180^{\circ}$

Step 3: Angles forming a linear pair sum to 180°

$m\angle {PRS}+m\angle {SRU}=180^{\circ}$

Step 4: By transitive property of equality

step 2 = step 3

$m\angle {PRS}+m\angle {VUW}=m\angle {PRS}+m\angle {SRU}$

Step 5: By algebra cancel the common terms in both side.

${m} \angle {VUW}={m} \angle{SRU}$

Step 6: By converse of corresponding angles postulate

Line TV || Line QS

Hence proved.

6 0

2 years ago

Which statements are true? Check all that apply.

Bumek [7]

Answer:

1,2,4

Step-by-step explanation:

A chord of a circle is a straight line segment whose endpoints both lie on the circle.

KJ is CHORD.

Tangency is point where tangent of circle touch it.

F is point of Tangency for FE.

Secant is the infinite line extension of a chord.

GN is a secant segment. 

4 0

3 years ago

Read 2 more answers

What is the asymptote for the graph of this logarithmic function? f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

2 years ago

Read 2 more answers