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3 years ago

8

Find the value of given expression

" title=" \sqrt[3]{9 - 1} " alt=" \sqrt[3]{9 - 1} " align="absmiddle" class="latex-formula">

2 answers:

svp [43]3 years ago

6 0

Answer:

$\sqrt[3]{9 - 1} = \sqrt[3]{8 } = \sqrt[3]{ {2}^{3} } = + - 2$

Anettt [7]3 years ago

4 0

Answer:

2 ans ......

Step-by-step explanation:

Solution:

= ³√9-1

= ³√8

= 2 ans....

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Subtract 9x^2-7x9x <br> 2<br> −7x from -4x^2+6−4x <br> 2<br> +6.

levacccp [35]

Answer:

18x^2+7x+12

Step-by-step explanation:

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4 years ago

if BA is extended all the way through A creating BF and A becomes the midpoint of BF, then what are the coordinates of F

gogolik [260]

Answer:

$F(2x_A-x_B,2y_A-y_B)$

Step-by-step explanation:

Let points A, B and F have coordinates $A(x_A,y_A),$ $B(x_B,y_B)$ and $F(x_F,y_F).$

If BA is extended all the way through A creating BF and A becomes the midpoint of BF, then the midpoint A of the segment BF has coordinates:

$\dfrac{x_B+x_F}{2}=x_A\\ \\\dfrac{y_B+y_F}{2}=y_A$

Express coordinates of point F:

$x_B+x_F=2x_A\Rightarrow x_F=2x_A-x_B\\ \\y_B+y_F=2y_A\Rightarrow y_F=2y_A-y_B$

Hence,

$F(2x_A-x_B,2y_A-y_B)$

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3 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below. See Attached Excel for Data. Assume t

motikmotik

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below.

16.5, 15.2, 15.4, 15.1, 15.3, 15.4, 16, 15.1

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans and fill in the blanks appropriately.

A 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is ( , ) ounces. (round to 3 decimal places)

Answer:

$99\% \: \text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

Step-by-step explanation:

Let us find out the mean amount of the 16-ounce beverage cans from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = 15.5$

Let us find out the standard deviation of the 16-ounce beverage cans from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = 0.4957$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where $\bar{x}$ is the sample mean and Margin of error is given by

$$ MoE = t_{\alpha/2} \cdot (\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample size, s is the sample standard deviation and is the t-score corresponding to a 99% confidence level.

The t-score corresponding to a 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.005 and DoF = 7

t-score = 3.4994

$MoE = t_{\alpha/2}\cdot (\frac{s}{\sqrt{n} } ) \\\\MoE = 3.4994 \cdot \frac{0.4957}{\sqrt{8} } \\\\MoE = 3.4994\cdot 0.1753\\\\MoE = 0.6134\\\\$

So the required 99% confidence interval is

$\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 15.5 \pm 0.6134\\\\\text {confidence interval} = 15.5 - 0.6134, \: 15.5 + 0.6134\\\\\text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

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4 years ago

Express the relationship between race time and average speed in two equivalent forms to complete a 400-miles

kow [346]

The time required for a race car to complete a 400 mile race is inversely proportional to the average speed that the car maintains. Express the relationship between race time and average speed in two equivalent forms.

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4 years ago