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natta225 [31]
3 years ago
7

Determine if the relation is a function. List the domain and range for each.

Mathematics
1 answer:
mamaluj [8]3 years ago
7 0

Answer:

This is a function, because for every x-value, there is exactly one y-value.

The domain is: {-5, -4, -3, -2}, and the range is {-2, -1, 0}

Let me know if this helps!

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Describe how to solve 4x = 36.​
netineya [11]

Answer:

hope this helps! :)

Step-by-step explanation:

4x=36

divide both sides of the equation by 4

4x / 4 = 36 / 4

Any expression divided by itself equals 1

x= 36 / 4

Calculate the quotient

36/4 = 9

<u>x=9</u>

4 0
3 years ago
What is 4and2/14 as an improper fraction in lowest terms
julia-pushkina [17]

Answer: 58 14ths

Step-by-step explanation:

multiply 14 by 4 to get 56 14ths, then add the 2

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What is the value of 5a + 7b <br> if a = 4 and b = 3?? <br> a : 41<br> b : 12<br> c : 43 <br> d : 35
MAXImum [283]
<h3>Answer:</h3><h3>41</h3><h3>Step-by-step explanation:</h3><h3>multiplication and addition</h3><h3>5x4=20</h3><h3>7x3=21</h3><h3>20+21=41</h3>
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Help will give brainlyist
denpristay [2]

Answer:

1. 25%

2. 150%

3. 3%

4. 75%

5. 60%

6. 210%

7. 10%

8. 1%

9. 40%

10. 87.5

11. 105%

12. 2%

Step-by-step explanation:

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NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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