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Bogdan [553]
2 years ago
7

43 grams of copper and 7grams other metals in a birdhouse, 83 grams of copper and 17 grams of other metals. Which one has more c

opper?
Mathematics
1 answer:
andrew-mc [135]2 years ago
6 0

Answer: cage  I

Step-by-step explanation:

Given

43 gm of copper and 7 gram of other metal

Another cage has 83 gram of copper and 17 gm of other metals

Here, the percentage of copper is

For the first case

\Rightarrow \dfrac{43}{43+7}\times 100=86\%

For the second case

\Rightarrow \dfrac{83}{83+17}\times 100=83\%

So, the cage-I has more percentage of copper

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^5 square root x^4 times ^5 square root x^4
Alla [95]

Answer:

Do 5x5 4 times

Step-by-step explanation:

4 0
2 years ago
What is this? Please answer with an explanation
Dima020 [189]

Answer:

Slope = -2

Step-by-step explanation:

Since, slope = \frac{\text{Rise}}{\text{Run}}

Rise = -(y-intercept)

Run = (x-intercept)

From the graph attached,

y - intercept = -(4) = -4

x - intercept = 2

Therefore, slope the line given in the graph attached will be,

Slope = \frac{-4}{2} = -2

Slope = -2

4 0
2 years ago
At a sand and gravel plant, sand is falling off a conveyor and onto a conical pile at a rate of 10 cubic feet per minute. The di
lawyer [7]

Answer:

0.0063 ft / min

Step-by-step explanation:

From the problem statement we have that the variation in volume with respect to time is equal 10, like this:

dV / dt = 10 ft ^ 3 / min

We know that the volume of the cone is given by the equation:

V = (1/3) * Pi * r ^ 2 * h

Now, we are mentioned that the diameter of the base of the cone is approximately three times the altitude, therefore:

2r = 3h, solving for r we have:

r = (3/2) * h, replacing the volume equation:

V = (1/3) * Pi * [(3h / 2) ^ 2] * h, solving we have:

V = (3/4) * Pi * h ^ 3

They ask us to calculate the change in height with respect to time, that is dh / dt

Therefore we derive both sides with respect to time, we have to:

dV / dt = (3/4) * Pi [3 * (h ^ 2) dh / dt] = (9/4) * pi * (h ^ 2) * dh / dt

reorganizing for dh / dt, we have:

dh / dt = [4/9 * pi * (h ^ 2)] * dV / dt

Knowing that h is 15 and dV / dt is 10, we replace these values:

dh / dt = [4/9 * 3.14 * (15 ^ 2)] * 10 = 0.0063 ft / min

0.0063 ft / min would be the change in height with respect to time.

4 0
3 years ago
A study shows that employees who begin their workday at 9:00 a.m. vary their times of arrival uniformly from 8:40 a.m. to 9:30 a
jeka94

Answer:

0.2 or 20%

Step-by-step explanation:

If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.

The range between 8:40 and 9:30 is 50 minutes.

The range between 9:00 and 9:10 is 10 minutes.

Therefore, the  probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:

P(9:00\leq X\leq 9:10)=\frac{10}{50}=0.20=20\%

The probability is 0.2 or 20%.

6 0
2 years ago
Each unit on the grid represents 2 kilometers. Find thedistance between Gabe's house and the library?
Lina20 [59]

Answer:

8km

Step-by-step explanation:

there are 4 unit between Gabe's house and the library so distance is 4×2=8km

5 0
3 years ago
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