How would you use distrubutive property for the eqaution 3(x+y)
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Answer:
<em>Sure hope this helps you :D</em>
He drank more than half of his drink... So we need to look for fractions greater than 1/2.
First, lets find equivalents of 1/2
If all of these fractions are equal to 1/2, then by adding to the numerator of these fractions, we'l have fractions greater than 1/2.
2 +1 3
__= ___
4 4
3/4 is greater than 1/2
Mike could have drunken 3/4 of the juice
4/6>1/2 Mike could have drunken 4/6 of the juice
5/8 is greater then 1/2 Mike could have drank 5/8 of the drink.
Answer=3/4, 4/6, 5/8 and many more possible fractions
First, lets find equivalents of 1/2
If all of these fractions are equal to 1/2, then by adding to the numerator of these fractions, we'l have fractions greater than 1/2.
2 +1 3
__= ___
4 4
3/4 is greater than 1/2
Mike could have drunken 3/4 of the juice
4/6>1/2 Mike could have drunken 4/6 of the juice
5/8 is greater then 1/2 Mike could have drank 5/8 of the drink.
Answer=3/4, 4/6, 5/8 and many more possible fractions