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3 years ago

11

A rectangular pool measuring 15*16 ft is surrounded by a walkway of uniform width. The total area of the pool and the walkway is

380 sq ft.
You are highly encouraged to draw a picture.

Part A) Write an equation to find the total area of the pool and the walkway (as a function of width of the walkway)

Part B) Solve the equation in part A to find the width of the walkway. Show your work.

1 answer:

Artist 52 [7]3 years ago

7 0

Answer:

The walkway has area 216 sq ft the pool has area (15 ft)(16 ft)=240 sq ft

Together a total area of (216 sq ft+225 sq ft)=441 sq ft since The pool and path form a square (the pool is 15ft x 15 ft and the path uniform around it)

The sides (s) of the total area are

s%5E2=441+sq+ft

s=sqrt%28441+sq+ft%29=21+feet

Each side of the total area spans the width of the path on one side then the width of the pool then the path on the other side so:

Total side=width of path + width of pool + width of path= 2*width of path+width of pool

width of path=(Total width-width of pool)/2

width of path=(21 feet - 15 feet)/2= 6 feet/2=3 Feet

ANSWER the width of the path is 3 feet

Step-by-step explanation:

sorry if i'm wrong

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A skate board ramp is built on an incline so that it rests on a porch that is 1.3m high. The bottom of the ramp is placed 2.5m f

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Step-by-step explanation:

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4 years ago

Line g has a slope of 9/5. line h is perpendicular to g. what is the slop of line h?<br>

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Answer:

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3 years ago

9. If LK MK, LK = 7x - 10, KN = x + 3, MN = 9x - 11, and KJ = 28, find LJ.

olasank [31]

Answer:

$LJ = 46$

Step-by-step explanation:

Given:

$LK = MK$

$LK = 7x - 10$

$KN = x + 3$

$MN = 9x - 11$

$KJ = 28$

Required:

LJ

Solution:

Step 1: create an equation to find the value of x

Since we are given that LK = MK, and LK = 7x - 10, let's find the expression for MK to get an equation.

$MK + KN = MN$ (segment addition postulate)

$MK = MN - KN$ (Subtract KN from each side)

$MK = (9x - 11) - (x + 3)$ (subtitution)

$MK = 9x - 11 - x - 3$

$MK = 9x - x - 11 - 3$

$MK = 8x - 14$

LK = MK, therefore,

$7x - 10 = 8x - 14$

Subtract 8x from each side

$7x - 10 - 8x = 8x - 14 - 8x$

$-x - 10 = -14$

Add 10 to both sides of the equation

$-x - 10 + 10 = -14 + 10$

$-x = -4$

Divide both sides by -1

$x = 4$

Step 2: Find LJ

$LJ = LK + KJ$ (segment addition postulate)

$LJ = (7x - 10) + (28)$

Plug in the value of x

$LJ = 7(4) - 10 + 28$

$LJ = 28 - 10 + 28$

$LJ = 46$

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