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marusya05 [52]
3 years ago
11

A rectangular pool measuring 15*16 ft is surrounded by a walkway of uniform width. The total area of the pool and the walkway is

380 sq ft.
You are highly encouraged to draw a picture.

Part A) Write an equation to find the total area of the pool and the walkway (as a function of width of the walkway)

Part B) Solve the equation in part A to find the width of the walkway. Show your work.
Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

The walkway has area 216 sq ft the pool has area (15 ft)(16 ft)=240 sq ft

Together a total area of (216 sq ft+225 sq ft)=441 sq ft since The pool and path form a square (the pool is 15ft x 15 ft and the path uniform around it)

The sides (s) of the total area are

s%5E2=441+sq+ft

s=sqrt%28441+sq+ft%29=21+feet

Each side of the total area spans the width of the path on one side then the width of the pool then the path on the other side so:

Total side=width of path + width of pool + width of path= 2*width of path+width of pool

width of path=(Total width-width of pool)/2

width of path=(21 feet - 15 feet)/2= 6 feet/2=3 Feet

ANSWER the width of the path is 3 feet

Step-by-step explanation:

sorry if i'm wrong

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