A high school sewing club has 11 members. In how many different ways can they choose a president and vice president?

2 answers:

6 0

Since the order matters Person A and B can be chosen as AB (A pres B vice pres) or BA (B president A Vice president)

When the order matters we are talking about permutations. How many permutations of 11 taken 2 at a time are there.
It can be written like this 11nPr 2
It means start at 11 and multiply by the next lower number
11 x 10 = 110 ways they can choose.
Extension of the concept:
If there had been three positions President, Vice President, and Treasurer
then it would be 11nPr3 or 11 x 10 x 9
Once again the answer to your problem is 110.

ahrayia [7]3 years ago

3 0

Answer: 110

Step-by-step explanation: Apex

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A coin collector has $45 in just dimes and quarters in a piggy bank he counted all the coins and there are 240 total how many ea

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The number of dimes are 100 and number of quarters are 140.

Step-by-step explanation:

Let the number of dimes be 'd' and quarters be 'q'.

Given:

The sum of amount is $45.

The total number of coins are 240.

1 dime = $0.10

∴ 'd' dimes = $\$0.10d$

1 quarter = $0.25

∴ 'q' quarters = $\$0.25q$

Now, as per question:

$d+m=240-----1\\0.1d+0.25q=45---2$

Multiplying equation (1) by -0.1 and adding the result to equation (2), we get:

$-0.1d-0.1q=240\times -0.1\\-0.1d-0.1q=-24\\0.1d+0.25q=45\\-----------\\0.15q=21\\q=\frac{21}{0.15}=140\\\\d=240-q=240-140=100$

Therefore, the number of dimes are 100 and number of quarters are 140.

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