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3 years ago

Need help pls help me on this question

Mathematics

2 answers:

ioda3 years ago

7 0

The answer should be A

Anettt [7]3 years ago

3 0

3x+45=72
Subtract 45 in both sides
Giving you 3x=27 divide by 3
X=9
Then do 72-45= 27
That’s your angle measure

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Hitman42 [59]

$\longmapsto$ The value of "x" is 5.

$\large\underline{\sf{Solution-}}$

Given that,

A trapezium ABCD in which AB || CD such that

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Now,

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$\rm \: \angle \: AOB \: and \: \angle \: COD \: \: \{vertically \: opposite \: angles \}$

$\rm \: \angle \:ABO \: and \: \angle \: CDO \: \: \{alternate \: interior \: angles \}$

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$\rm \longmapsto\:(x - 1)(x + 4) = {(x + 1)}^{2}$

$\rm \longmapsto\: {x}^{2} - x + 4x - 4 = {x}^{2} + 1 + 2x$

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$\rm \longmapsto\: 3x - 2x= 1 +4$

$\bf\longmapsto \:x = 5$

7 0

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vazorg [7]

Answer:

x=16

(5x + 27)° =5(16)+27=80+27=107

(5x – 7)º= 5(16)-7=80-7=73

Step-by-step explanation

supplementary angle=180

(5x + 27)° + (5x – 7)º=180

5x+27+5x-7=180

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10x=160

x=160/10

x=16

(5x + 27)° =5(16)+27=80+27=107

(5x – 7)º= 5(16)-7=80-7=73

107+73=180

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