Okay, it's the equation to how find area any other way. A=L×W
This means *picture above*
So then you count over each line meaning 1.
This means L=9 and a 1/2. Since its in between the 2 an 3 on the x-axis.
Now for W or width. It equals 3 since you can count 2 lines and one either ends of the polygon is 1/2 each this creates one when added together.
All you do from there is multiply 9 and 3. This should give you A=area.
Part A:
There are 25 blocks for the length, and the length of each is 5.5 inches. 5.5x25=137.5
There are 9 blocks for the height, and each is 2.75 inches. 2.75x9=24.75
Since we're trying to find how much longer the length is to the width, we find the difference. 137.5-24.75=112.75
So part A answer is <em><u>112.75 (or 112¾)</u></em>
Part B:
We know the length is 137.5 and the height is 24.75. To find how many times longer the length is, we need to divide to see how many 24.75 can go into 137.5.
137.5÷24.75=5.55
So the answer to part B is <u><em>5.55. Given the context, the answer would probably be 5, because that's how many entire height can fit.</em></u>
<u><em /></u>
Sorry if it's wrong lol
We assume that the function is as follows:
![f^{-1_{}}(2)=?](https://tex.z-dn.net/?f=f%5E%7B-1_%7B%7D%7D%282%29%3D%3F)
Then, we have that:
![f^{-1}(x)=\frac{1}{f(x)}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Cfrac%7B1%7D%7Bf%28x%29%7D)
Thus, if we have that:
![f(2)=-2\Rightarrow f^{-1^{}_{}}(x)=\frac{1}{f(x)}\Rightarrow f^{-1}(2)=\frac{1}{f(2)}=\frac{1}{-2}\Rightarrow f^{-1}(2)=-\frac{1}{2}](https://tex.z-dn.net/?f=f%282%29%3D-2%5CRightarrow%20f%5E%7B-1%5E%7B%7D_%7B%7D%7D%28x%29%3D%5Cfrac%7B1%7D%7Bf%28x%29%7D%5CRightarrow%20f%5E%7B-1%7D%282%29%3D%5Cfrac%7B1%7D%7Bf%282%29%7D%3D%5Cfrac%7B1%7D%7B-2%7D%5CRightarrow%20f%5E%7B-1%7D%282%29%3D-%5Cfrac%7B1%7D%7B2%7D)
Therefore, the value for the function is f^-1(2) = -1/2 or
8.75-4.85= 3.90= cost of 6 bananas
3.9/6=0.65= cost of one banana
.65*4=2.60= cost of 4 bananas
4.85-2.60= 2.25= cost of 3 apples
2.25/3=.75= cost of an apple