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kotykmax [81]
3 years ago
15

Pls help im talkin 25 here

Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer: i do know girl

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(a−2b)^3 when a=−4 and b=−12
erma4kov [3.2K]

Answer:

8,000

Step-by-step explanation:

You can simplify it to (-4+24)^3a

7 0
2 years ago
Maurice averaged 79 points for 6 tests. How many more points must he score in the next text to raise his average to 80.
Lady bird [3.3K]

Answer:

86 is the score that Maurice must get to average his score to 80

8 0
2 years ago
The perimeter of rectangle is twice the sum of its length and its width.the perimeter is 22 meters and its length is 2 meters mo
romanna [79]
P = 2(L + W)
P = 22
L = 2W + 2

22 = 2(2W + 2 + W)
22 = 2(3W + 2)
22 = 6W + 4
22 - 4 = 6W
18 = 6W
18/6 = W
3 = W.....this is the width

L = 2W + 2
L = 2(3) + 2
L = 6 + 2
L = 8 meters <=== this is the length
6 0
3 years ago
Read 2 more answers
If the volume of a box is 2x3 + 4x2 − 30xwhich of the dimensions are possible with the given x-value?
Kipish [7]

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

Step-by-step explanation:

The given is,

                        2 x^{3} + 4 x^{2} -30x................................(1)

Step:1

    Check for option A,

             x = 1, dimensions 8 by 9 by 1  

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(2)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                     = 72............................................(3)

            From equation (2) and (3)

                                -24 ≠ 72

            So, X=1; dimensions 8 by 9 by 1 is not possible.

   Check for option B,

             x = 1, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(4)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30.........................................(5)

            From equation (4) and (5)

                                -24 ≠ 30

            So, X=1; dimensions 2 by 5 by 3 is not possible.

   Check for option C,

            x = 4, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72.............................................(6)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30............................................(7)

            From equation (6) and (7)

                               72 ≠ 30

            So, X=4; dimensions 2 by 5 by 3 is not possible.

    Check for option C,

            x = 4, dimensions 8 by 9 by 1

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72............................................(8)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                    = 72............................................(9)

            From equation (8) and (9)

                               72 = 72

            So, X=4; dimensions 8 by 9 by 3 is possible.

Result:

           The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

         

4 0
3 years ago
Which graph represents the function f(x) = (x – 3)2?
Snowcat [4.5K]

Answer:

Graph 3 on Edg.

Step-by-step explanation:

6 0
3 years ago
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