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topjm [15]
3 years ago
6

5. Which geh metches the inegality?" x < 6

Mathematics
1 answer:
Gnesinka [82]3 years ago
8 0

Answer:

the right answer is option 4

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Which inequality is true when G = 3/5 ?
GREYUIT [131]

Answer:

D. 15G > 9

Step-by-step explanation:

Given: G = 3/5

Here we have to check each options and find which is true.

Let's start from A.

G - 1 > 2/5

G > 2/5 + 1

G > 7/5 is not true.

B. -10G > 6

Dividing both sides by -10 , we get

G < -6/10

G < -3/5 Is not true.

C. 1 2/5 + G > 3

Now convert 1 2/5 to improper fraction.

1 2/5 = 7/5

7/5 + G > 3

G > 3 - 7/5

G > (15 - 7)/5

G > 8/5 is not rule.

D. 15G > 9

Dividing both sides by 15, we get

G > 9/15

Now we have to simplify 9/15

G > 3/5 which is true.

Answer: D. 15G > 9

Thank you.

4 0
4 years ago
If you are asked to compare two numbers, what two operations might you use? Why?
Oduvanchick [21]
Subtraction: get how many units a number exceeds the other
<span>Division: lets you know how much a number is larger (or smaller) than the other.</span>
5 0
3 years ago
Two friends argue over who brushes their teeth more often. To settle the argument, they keep track of the number of mornings and
Llana [10]

Answer: D. Arabella. She has a 0.79 probability of brushing both times.

Step-by-step explanation:

A.P.E.X

7 0
3 years ago
Read 2 more answers
If the outlier of this data set is removed, which statement about the data is true?
OverLord2011 [107]
Hello!

First you have to find what the outlier is

Since 55 if a number way higher than the rest of the data it is the outlier

Removing the outlier does not change the mode

Now we look at what the median is without the 55

The median is 40 when we remove the 55

The answer is A

Hope this helps!
8 0
4 years ago
Read 2 more answers
Solve by using logarithms, not the same base. I have absolutely no clue how to solve so any help would be amazing, thanks
mariarad [96]

Answer:

-5/48

Step-by-step explanation:

(8 · 2⁷ˣ)⁴ = (1/16)⁵ˣ · 128

<em>Take log of both sides.</em>

log (8 · 2⁷ˣ)⁴ = log ((1/16)⁵ˣ · 128)

<em>Use log exponent/product rules.</em>

4 log (8 · 2⁷ˣ) = log (1/16)⁵ˣ + log 128

<em>Use log exponent/product rules.</em>

4 (log 8 + log (2⁷ˣ)) = 5x log (1/16) + log 128

<em>Use log exponent rule.</em>

4 (log 8 + 7x log 2) = 5x log (1/16) + log 128

<em>Distribute.</em>

4 log 8 + 28x log 2 = 5x log (1/16) + log 128

<em>Write as powers of 2.</em>

4 log 2³ + 28x log 2 = 5x log (2⁻⁴) + log 2⁷

<em>Use log exponent rule.</em>

12 log 2 + 28x log 2 = -20x log 2 + 7 log 2

<em>Combine like terms.</em>

5 log 2 + 48x log 2 = 0

<em>Divide by log 2.</em>

5 + 48x = 0

<em>Solve for x.</em>

x = -5/48

6 0
3 years ago
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