2 years ago

PLZ HELP ME I ONLY HAVE 10 more mins left

Mathematics

1 answer:

IceJOKER [234]2 years ago

3 0

thats the graph for the equation.

hope it helps

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Show that if f(n) is O(g(n)) and d(n) is O(h(n)) then f(n) + d(n) is O(g(n) + h(n)).

GaryK [48]

$f(n)\in\mathcal O(g(n))$ is to say

$|f(n)|\le M_1|g(n)|$

for all $n$ beyond some fixed $n_1$ .

Similarly, $d(n)\in\mathcal O(h(n))$ is to say

$|d(n)|\le M_2|h(n)|$

for all $n\ge n_2$ .

From this we can gather that

$|f(n)+d(n)|\le|f(n)|+|d(n)|\le M_1|g(n)|+M_2|h(n)|\le M(|g(n)|+|h(n)|)$

where $M$ is the larger of the two values $M_1$ and $M_2$ , or $M=\max\{M_1,M_2\}$ . Then the last term is bounded above by

$M(|g(n)|+|h(n)|)\le2M\max\{|g(n)|,|h(n)|\}$

from which it follows that

$f(n)+d(n)\in\mathcal O(\max\{g(n),h(n)\})$

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3 years ago

I need help with the answer to this question.

olasank [31]

Explanation:

9-3=6

(Check your work)

3+6=9

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6÷1/3=18

(Check your work)

(6×3=18)

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18+1=19

<u>Therefore,</u>

the answer is 19!

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Alexxx [7]

Answer:

Step-by-step explanation:

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SashulF [63]

Answer:

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Step-by-step explanation:

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