There is no photo that is shown?
Answer: angle B will be 90°
Sum of the angles = 180°
Answer:
I'm pretty sure it's the 8 feet deep hole
Step-by-step explanation:
You're earning 8 dollars so that can't be negative.
Temperature can be negative but it doesn't have the - in front of it.
It would be a confusing question if that's the answer because then you'd be basically guessing at it.
I don't think it's the throw because you can't actually throw in negative/throw backwards for it to be negative.
8 feet hole is the only one that makes sense, since you're going down
Answer:
a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

a)Less than 19.5 hours?
This is the pvalue of Z when X = 19.5. So



has a pvalue of 0.4013.
40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b)Between 20 hours and 22 hours?
This is the pvalue of Z when X = 22 subtracted by the pvalue of Z when X = 20. So
X = 22



has a pvalue of 0.8413
X = 20



has a pvalue of 0.5
0.8413 - 0.5 = 0.3413
34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.
Answer:
<h3>The value C(t) of the car after 5 years is $12709.</h3>
Step-by-step explanation:
Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.
<h3>To find the value C(t) of the car after 5 years:</h3>
Initial value 
Depreciation rate is 
<h3>∴ r=0.045</h3>
Period , t=5 years

Substitute the values we get



∴ 
<h3>The value C(t) of the car after 5 years is $
12709</h3>