Answer:
Relative frequency
0.214
0.268
0.446
0.071
Total 1
Step-by-step explanation:
The relative frequency is computed by dividing the individual frequencies to the sum of frequencies.
sum of frequencies=12+15+25+4=56
Class Relative Frequency
10-20 12/56=0.214
20-30 15/56=0.268
30-40 25/56=0.446
40-50 4/56=0.071
Total 12/56+15/56+25/56+4/56=56/56=1
Well, if it is increasing at a fixed rate of 2 mm/s, then the volume would still be increasing at a rate of 2 mm/s when the diameter is 80 mm, if I understand your question correctly.
Answer:
all work is shown and pictured
Answer:
It is balance she need to use. Answer is B.
Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.