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3 years ago

S - k + x; when s = 7, k = 4, x = 6what does this mean someone help quick

Mathematics

1 answer:

sveticcg [70]3 years ago

4 0

Answer:

you just plug in those numbers... 7-4+6 = 9

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Find an equation of the tangent line to the hyperbola y = 3/x at the point (3, 1).

Vesna [10]

Let's find the derivative of that hyperbola in order to find a slope formula to help us with this equation. We already have an x and y value. The derivative is found this way: $y'= \frac{x(0)-3(1)}{x^2}$ so $y'=- \frac{3}{x^2}$ . The derivative supplies us with the slope formula we need to write the equation. Sub in the x value of 3 to find what the slope is: $y'=- \frac{3}{3^2}=- \frac{3}{9}=- \frac{1}{3}$ . So in our slope-intercept equation, x = 3, y = 1, and m = -1/3. Use these values to solve for b. $1=- \frac{1}{3}(3)+b$ so b = 2. The equation, then, for the line tangent to that hyperbola at that given point is $y=- \frac{1}{3}x+2$

6 0

4 years ago

Given the set of data: 24, 43, 65, 12, 31, 78, 43, 24, 25, 18, 29, 53, 18, 23, 20, 43, 53, 25 Determine the quartiles.

worty [1.4K]

Answer:

Lower quartile= 4.75

Middle quartile= 9.5

Upper quartile= 14.25

Step-by-step explanation:

The given date set is 24, 43, 65, 12, 31, 78, 43, 24, 25, 18, 29, 53, 18, 23, 20, 43, 53, 25

On counting them we notice that it's number of element is 18

So N = 18

Arranging them in ascending order gives

12,18,18,20,23,24,24,25,25,29,31,43,43,43,53,53,65,78

Lower quartile= (N+1)*1/4

Lower quartile= (18+1)/4

Lower quartile= 19/4

Lower quartile= 4.75

Middle quartile= (N+1)*2/4

Middle quartile= (18+1)*2/4

Middle quartile= (19)*2/4

Middle quartile= 9.5

Upper quartile= (N+1)*3/4

Upper quartile= (18+1)*3/4

Upper quartile= (19)*3/4

Upper quartile= 14.25

Inter quartile range = upper quartile- minutes lower quartile

= 14.25-4.75

= 9.5

4 0

3 years ago

ABC is isosceles.<br>m < a = 3x + 40 and m < c = x + 50<br>what is m < a ??

il63 [147K]

Answer:

55°

Step-by-step explanation:

<u>It is assumed the angles A and C are congruent:</u>

3x + 40 = x + 50
3x - x = 50 - 40
2x = 10
x = 5

m∠A = 3*5 + 40 = 55°

7 0

3 years ago

Read 2 more answers

Which value is equivalent to (7x5x2/7x3)^2 x (5^0/2^-3)^3 x2^-9?

koban [17]

Answer:

100/9

Step-by-step explanation:

(7*5*2/7*3)² * (5^0/2^-3)³ * 2^-9

Solution:

We know that any number with power 0 = 1

(7*5*2/7*3)² * (1/2^-3)³ * 2^-9

Now cancel out 2 by 2

= (7*5*2/7*3)² * (1/1^-3)³ * 1^-9

=(70/21)² * (1)³/(1^-3)³ * 1^-9

=(10/3)^2 * 1/1^-1 * 1/1^9

=100/9 *1 *1

=100/9....

7 0

4 years ago

Given the equation of the line -6x + 2y = 10

Andre45 [30]

Answer:

x= 1 /3 y+ −5 /3

y=3x+5

Step-by-step explanation:

brainliest?

5 0

3 years ago

Read 2 more answers