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shusha [124]
3 years ago
14

What is the solution to | 2x-4| >8?

Mathematics
1 answer:
Serga [27]3 years ago
8 0
| 2x-4| \ \textgreater \ 8 \\ \\ 2x - 4 \ \textgreater \  8 \ , \ -(2x - 4) \ \textgreater \  8 \ / \ break \ problem \ into \ 2 \ equations \\ \\ first \ equation  \\ \\ 2x \ \textgreater \  8 + 4 \ / \ add \ 4 \ to \ each \ side \\ \\ 2x \ \textgreater \  12 \ / \ simplify \\ \\ x \ \textgreater \   \frac{12}{2} \ / \ divide\ each \ side \ by \ 2 \\ \\ x \ \textgreater \  6 \ / \ simplify \\ \\ second \ equation \\ \\ -2x + 4 \ \textgreater \  8 \ / \ simplify \\ \\ -2x \ \textgreater \  8 - 4 \ / \ subtract \ 4 \ from \ each \ side \\ \\ -2x \ \textgreater \  4 \ / \ simplify \\ \\  x \ \textless \   \frac{4}{-2} \ / \ divide \ each \ side \ by \ -2 \\ \\ 
\\ \\ x \ \textless \  -  \frac{4}{2} \ / \ simplify \\ \\ x \ \textless \  - 2 \ / \ simplify \\ \\ collect \ solutions \\ \\ x \ \textgreater \  6 \ , \ x \ \textless \  -2 \\ \\

So, your answer to this problem is x > 6 and x < -2.
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Area of  a circle= πr²
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What is the best approximation for the perimeter of a semicircle with a diameter of 12 cm?
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Answer:

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