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3 years ago

Help me solve this please!!

Mathematics

2 answers:

mars1129 [50]3 years ago

5 0

Answer:

The answer is

$a = 9 \sqrt{3} \: and \: b = 9$

soldier1979 [14.2K]3 years ago

3 0

Answer:

Step-by-step explanation:

Using the sine/ cosine ratios in the right triangle and the exact values

sin60° = $\frac{\sqrt{3} }{2}$ , cos60° = $\frac{1}{2}$

sin60° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{18}$ ( multiply both sides by 18 )

18 × sin60° = a , then

a = 18 × $\frac{\sqrt{3} }{2}$ = 9 $\sqrt{3}$

-------------------------------

cos60° = $\frac{adjacent}{hypotenuse}$ = $\frac{b}{18}$ ( multiply both sides by 18 )

18 × cos60° = b , then

b = 18 × $\frac{1}{2}$ = 9

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