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Tom [10]
3 years ago
7

A sucrose solution is prepared by dissolving 18.50 g of sucrose C12H22011, in 150 g

Chemistry
1 answer:
Ratling [72]3 years ago
8 0

Answer:

B. 0.36

Explanation:

18.5/342.3 = .054 mols of Surcrose

150g of water = .15kg

molality = mols/kg of solvent

.054/.15 = 0.36 molalality

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