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3 years ago

Graph the function. f(x)=5/9(x+9)(x+3)

Mathematics

1 answer:

Zolol [24]3 years ago

7 0

Answer: i inserted two just incase but tell me if i am wrong

Step-by-step explanation:

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The minimum height for riding on the Super Screaming Spinner at the theme park is 52 inches. Which of the following expressions

Hoochie [10]

Answer:

$h\geq 52\ in$

Step-by-step explanation:

Let

h-------> the minimum height for riding on the Super Screaming Spinner at the theme park

we know that

the height may not be less than $52\ in$

$h\geq 52\ in$ -------> inequality that represent the situation

7 0

3 years ago

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The cost of a car rental is twenty-five dollars a day plus ten cents a mile. What is the total cost, in dollars, if the car is r

Fudgin [204]

Answer:

The total cost is D) $141

Step-by-step explanation:

To solve we can use the equation: $y=25d+0.10m$

d= number of days m= number of miles

We know both of these values so we can plug them in and solve.

y= 25(3) + 0.10(660)

y= 75 + 66

y = 141

4 0

3 years ago

If 10% of men are bald, what is the probability that fewer than 100 in a random sample of 818 men are bald? (Answers must be in

Greeley [361]

Answer: the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

Step-by-step explanation:

Given that;

p = 10% = 0.1

so let q = 1 - p = 1 - 0.1 = 0.9

n = 818

μ = np = 818 × 0.1 = 81.8

α = √(npq) = √( 818 × 0.1 × 0.9 ) = √73.62 = 8.58

Now to find P( x < 100)

we say;

Z = (X-μ / α) = ((100-81.8) / 8.58) = 18.2 / 8.58 = 2.12

P(x<100) = P(z < 2.12)

from z-score table

P(z < 2.12) = 0.9830

Therefore the probability that fewer than 100 in a random sample of 818 men are bald is 0.9830

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3 years ago

At a quiz competition, for every question team A answered correctly, team B answered 2 questions correctly. The ratio of the num

a_sh-v [17]

A : B
1 : 2

anything to ask please pm me

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3 years ago

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James and Sarah went out to lunch. The price of lunch for both of them was $20. They tipped their server 15% of that amount.

Wittaler [7]

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{15\% of 20}}{\left( \cfrac{15}{100} \right)20}\implies 3~\hfill \begin{array}{llll} \stackrel{\textit{price + tip}}{20+3\implies 23}\\\\ \stackrel{\textit{each one paid half of 23}}{11.5} \end{array}$

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3 years ago

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