All categories

3 years ago

The absolute value of 7−12is

Mathematics

2 answers:

Leno4ka [110]3 years ago

7 0

Answer:

Step-by-step explanation:

Do you mean 7-12, or 7/(-12)?

7-12 = -5, so the absolute value of 7-12 is 5.

The absolute value of 7/(-12) is 7/12.

MakcuM [25]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

Sets<br> Let A = {1, 2, 3, 8} and {x | x is an even whole number less than 9}, find An B <br>

spin [16.1K]

A={1,2,3,8}

B={x|x is an even whole no less than 9}

B={2,4,6,8}

Now

$\\ \sf\longmapsto A\cap B=\{2,8\}$

6 0

3 years ago

Read 2 more answers

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

2 years ago

Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

juin [17]

Answer:

108 cm^2

Step-by-step explanation:

The lateral surface area of a pyramid is given as

LSA= 1/2×perimeter of the base×slant height

base is hexagon with side 3 cm , therefore, perimeter of the base

=6×3=18 cm

slant height = 12 cm

thus, LSA = 1/2×18×12 = 108 cm^2

4 0

3 years ago

3. Resuelve el triángulo con A = 30º, a = 3 cm y b = 4 cm y comprueba que hay dos soluciones posibles.

Igoryamba

Answer:

41.8°

Step-by-step explanation:

Resolvemos esta pregunta usando la regla del seno

a / sin A = b / sin B

Estamos despejando el ángulo B

Por lo tanto:

3 / sin 30 = 4 / sin B

Cruz multiplicar

3 × sin B = sin 30 × 4

sin B = sin 30 × 4/3

B = arco sin [sin 30 × 4/3]

B = 41.81031 °

Aproximadamente = 41.8 °

4 0

3 years ago

Complete the pattern 5,10,30,60,180, ?

krek1111 [17]

540 is the answer because the doubled the first number to get the second number and multiplyed that by 3 to get the third number

4 0

4 years ago

Read 2 more answers

The absolute value of 7−12is ​

The absolute value of 7−12is