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2 years ago

H(j + i) - k5 + h when h = 3, i = 4, j = 2, and k = 1 pls put how you did it

Mathematics

1 answer:

VikaD [51]2 years ago

6 0

Answer:

Step-by-step explanation:

First you want to plug in all the numbers where the letters are

h ( j + i )- k(5) + h

3 ( 2 + 4 )- 1(5) + 3

After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.

6 + 12 - 1(5) + 3

Then you just follow PEMDAS to solve for the rest

6 + 12 - 5 + 3

18 - 5 + 3

13 + 3

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The equation represents height as a function of time.

The bullet was in the air for 75 seconds.

The equation is given as:

$h(t) = -16t^2 + 1200t$

The time spent in the air is the time it takes the bullet to land on the ground.

When the bullet is on the ground, the height is:

$h(t) = 0$

So, we have:

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Factor out t

$t(-16t + 1200) = 0$

Split

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$t = 0$ represents when the shot is fired.

So, we solve for t in $-16t + 1200 = 0$

Collect like terms

$16t = 1200$

Divide both sides by 16

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Hence, the bullet was in the air for 75 seconds