Answer:
This is an arithmetic sequence with a common difference <em>d</em> of -5
Step-by-step explanation:
When you find out <em>d</em>, you realize the difference between the numbers to be -5. Since it is <em>d</em> and not common ratio <em>r</em>, it is an arithmetic sequence.
Using it's concept, the range of the function is given as follows:
0 ≤ m ≤ 1200.
<h3>What is the range of a function?</h3>
The range of a function is the set that contains all possible output values for the function.
For this problem, we have to consider these two bullet points next, considering the mass is the output value of the function.
- The smallest possible mass for the substance is of 0 grams, as after the substance decays to 0 grams, it will not assume a negative value, it will just disappear.
- The greatest possible mass for the substance is the initial mass of 1200 grams, as the substance does not adquire mass with time, it just loses it.
Considering these masses, the range of the function is given as follows:
0 ≤ m ≤ 1200.
More can be learned about the range of a function at brainly.com/question/10197594
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Answer:
Y=7
Step-by-step explanation:
(3y+5)= -4 -8y +9 + 77
-5 -5
3y= -9 - 8y + 9 + 77
+9 -9
3y= -8y + 77
+8y +8y
11y = 77
11y/11 77/11
y = 7
1. subtract 5 from both sides
2. add -9 and +9 and you get 0
3. add 8y to both sides
4. divide both sides by 11
5. you get y=7
Answer:
The enrollment after 5 years is 10,724
Step-by-step explanation:
Generally, we can have the depreciation formula written as follows;
A = P(1 - r)^t
A is the number of enrollment in after a certain number of years t
P is the initial population which is 13,500
r is the rate of depreciation which is 4.5% = 4.5/100 = 0.045
t = 5 years
Substituting these values, we have it that;
A = 13,500(1-0.045)^5
A = 10,723.84
Answer:
$383.20
Step-by-step explanation:
28.74 ÷ 3 = $9.58 per hour
9.58 x 40 = 383.20
