1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alekssr [168]
3 years ago
9

Do u want branlist answer this please

Mathematics
2 answers:
alisha [4.7K]3 years ago
8 0

Answer:b

Step-by-step explanation:

a line always has 180 degrees so u just subtract 180-85=95 or what ever the angle is

Talja [164]3 years ago
4 0
It’s b
AHHHHHHHHHHHHHHHHHHHHHHHHH had to make it 20 letters
You might be interested in
What values of x makes -6x =12 true<br>​
Licemer1 [7]

Answer:

<h3>=> —6x = 12</h3><h3>=> —x = 12/6</h3><h3>=> —x = 2</h3>

<h2>=> x = —2</h2>

Step-by-step explanation:

hope it's helpful :-)

8 0
3 years ago
Read 2 more answers
If the angles 2xº and 4yº<br> are<br> complementary, find the value of x + 2y.
ivolga24 [154]

Answer:

Solution given:

the angles 2xº and 4yºare complementary

so

2x+4y=90°

dividing both side by 2we get

x+2y=45°

<u>the value of x + 2y</u><u> </u><u>i</u><u>s</u><u> </u><u>4</u><u>5</u><u>°</u><u>.</u>

3 0
3 years ago
Suppose you and your 4 friends (5 people) are dressing up as the 6 main characters of the first Avengers movie: Iron Man, Hulk,
Dennis_Churaev [7]

Answer:

720

Step-by-step explanation:

If every person has to choose a different character, the first person to choose a character has 6 options, the second has 5, the third has 4, the fourth has 3, and the last person has only two options. Therefore, the total number of ways you can do this if all 5 people dress up as a different character is:

n=6*5*4*3*2\\n=720

There are 720 ways.

5 0
3 years ago
Graph the line with the equation y=1/3x+1
devlian [24]

Answer:

See photo

Step-by-step explanation:

\frac{1}{3} = \frac{rise}{run}

1 = slope intercept

6 0
3 years ago
A plane flying horizontally at an altitude of 1 mile and a speed of 510 mi/h passes directly over a radar station. Find the rate
sdas [7]

Answer:

442 miles

Step-by-step explanation:

Given

To properly solve this question, I illustrate some given parameters using attached image

From the image, apply Pythagoras theorem

x^2 + 1^2 = y^2

Differentiate w.r.t time (t)

2x\frac{dx}{dt} + 0 = 2y\frac{dy}{dt}

2x\frac{dx}{dt} = 2y\frac{dy}{dt}

Divide both sides by 2

x\frac{dx}{dt} = y\frac{dy}{dt}

From the question, we have that the plan travels are 510mi/h.

This implies that:

\frac{dx}{dt} = 510mi/h

So, we then calculate the value of x when the distance (y) is 2mi i.e.:

y = 2mi

Apply Pythagoras theorem

x^2 + 1^2 = y^2

x^2 + 1^2 = 2^2

x^2 + 1 = 4

x^2 = 4-1

x^2 = 3

x = \sqrt 3

So, the expression becomes:

x\frac{dx}{dt} = y\frac{dy}{dt}

\sqrt 3 * 510 = 2* \frac{dy}{dt}

\frac{\sqrt 3 * 510}{2} =  \frac{dy}{dt}

\sqrt 3 * 255 =  \frac{dy}{dt}

\frac{dy}{dt} = 255\sqrt 3

\frac{dy}{dt} = 255 * 1.7321

\frac{dy}{dt} = 441.655

\frac{dy}{dt} = 442

<em>Hence, the distance is 442 miles</em>

7 0
3 years ago
Other questions:
  • Simplify.<br><br> 2x5 - 6x2 + 4x4y<br> -------------------------<br> 2x
    7·1 answer
  • Solve for x. 5x+4-5=54x+6/6
    15·2 answers
  • 2. A fair dice is rolled. What is the probability that a number divisible by 3 is rolled?
    14·1 answer
  • I need help please explain how to do these two question as I did the rest of them. I just don't understand these.
    15·1 answer
  • two toy rockets are launched straight up into the air. the height, in feet, of each rocket at t seconds after launch is given by
    5·1 answer
  • Solve for x please help !!!!!!!
    10·1 answer
  • Can someone help me please?
    8·1 answer
  • (0,8)<br> (-2,0). What is the equation of the linear graph shown?
    5·1 answer
  • 12×(3 + 2²)÷2-10= ??????????<br><br><br><br><br><br><br>​
    6·2 answers
  • Can someone help me quickly? giving brainliest to first answer. &lt;3
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!