Answer:
20π ft²
Step-by-step explanation:
Calculate the circumference of this circular area: C = 2πr, where r is the radius:
C = 2π(10 ft) = 20π ft²
It's given in the question,
P, Q, V and K are collinear.
VP = 14x + 4
PK = x + 630
VQ = 17x + 6
KQ = 11x + 5
By segment addition postulate,
KQ + VQ + VP = KP
Substitute the values in the expression,
(11x + 5) + (17x + 6) + (14x + 4) = x + 630
(11x + 17x + 14x) + (5 + 6 + 4) = x + 630
42x + 15 = x + 630
42x - x = 630 - 15
41x = 615
x = 
x = 15
Therefore, value of VP = (14x + 4)
= 14(15) + 4
= 214 units
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Answer:
Let's solve your equation step-by-step.
4 ( 8x − 1 ) = 19 + 32x
Step 1: Simplify both sides of the equation.
4 ( 8x − 1 ) = 19 + 32x
( 4 ) ( 8x ) + ( 4 ) ( −1 ) = 19 + 32x ( Distribute )
32x + −4 = 19 + 32x
32x − 4 = 32x + 19
Step 2: Subtract 32x from both sides.
32x − 4 − 32x = 32x + 19 − 32x
−4 = 19
Step 3: Add 4 to both sides.
−4 + 4 = 19 + 4
0 = 23
Answer:
There are no solutions.
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Answer:
21
Step-by-step explanation:
Answer:
438,012 ways.
Step-by-step explanation:
We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.
Since the letters and digits can be repeated, so we will use fundamental principal of counting.
For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.
We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.
So we can choose coupon code is following ways:

Therefore, we can choose coupon codes in 438,012 ways.