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2 years ago

What is 1836837292 times 816282?

Mathematics

2 answers:

seraphim [82]2 years ago

7 0

Answer:

1499377218388344

Step-by-step explanation:

LiRa [457]2 years ago

5 0

Answer:

The product is 1.4993772e+15.

Step-by-step explanation:

Thanks for the points! Brainliest? Thanks!

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A taxi charges a flat rate of 1.75, plus an additional 0.65 per mile. If Erika has at most 7.60 to spend on the cab ride, how fa

pshichka [43]

First, we subtract 1.75 from 7.60. This leaves us with 5.85 for miles. We divide 5.85 by 0.65 to get the number of miles she could travel. This gives us 9. So, Erika could travel 9 miles.

4 0

2 years ago

Graph the equation. 2y-9= -2 please show work

Ivan

Answer:5.5

Step-by-step explanation:

2y-9=-2

+9 +9

2y/2 = 11/2

5.5

7 0

2 years ago

Given the second order homogeneous constant coefficient equation y′′−4y′−12y=0 1) the characteristic polynomial ar2+br+c is r^2-

Vitek1552 [10]

Answer:

The initial value problem $y(x) = 4 e^{-2x} -3 e^{6 x}$

Step-by-step explanation:

Step1:-

a) Given second order homogenous constant co-efficient equation

$y^{ll} - 4y^{l}-12y=0$

Given equation in the operator form is $(D^{2} -4D-12)y=0$

Step 2:-

b) Let f(D) = $(D^{2} -4D-12)y$

Then the auxiliary equation is $(m^{2} -4m-12)=0$

Find the factors of the auxiliary equation is

$m^{2} -6m+2m-12=0$

m(m-6) + 2(m-6) =0

m+2 =0 and m-6=0

m=-2 and m=6

The roots are real and different

The general solution $y = c_{1} e^{-m_{1} x} + c_{2} e^{m_{2} x}$

the roots are $m_{1} = -2 and m_{2} = 6$

The general solution of given differential equation is

$y = c_{1} e^{-2x} + c_{2} e^{6 x}$

Step 3:-

C) Given initial conditions are y(0) =1 and y1 (0) =-26

The general solution of given differential equation is

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$ .....(1)

substitute x =0 and y(0) =1

$y(0) = c_{1} e^{0} + c_{2} e^{0}$

$1 = c_{1} + c_{2}$ .........(2)

Differentiating equation (1) with respective to 'x'

$y^l(x) = -2c_{1} e^{-2x} + 6c_{2} e^{6 x}$

substitute x= o and y1 (0) =-26

$-26 = -2c_{1} e^{0} + 6c_{2} e^{0}$

$-2c_{1} + 6c_{2} = -26$ .............(3)

solving (2) and (3) by using substitution method

$substitute c_{2} =1- c_{1}$ in equation (3)

$-2c_{1} + 6(1-c_{1}) = -26$

on simplification , we get

$-2c_{1} + 6(1)-6c_{1}) = -26$

$-8c_{1} = -32$

dividing by'8' we get $c_{1} =4$

substitute $c_{1} =4$ in equation $1 = c_{1} + c_{2}$

so $c_{2} = 1-4 = -3$

now substitute $c_{1} =4 and c_{2} =-3$ in general solution

$y(x) = c_{1} e^{-2x} + c_{2} e^{6 x}$

$y(x) = 4 e^{-2x} -3 e^{6 x}$

now the initial value problem

$y(x) = 4 e^{-2x} -3 e^{6 x}$

7 0

3 years ago

Given the figure is a kite. Find the indicated measures.

tigry1 [53]

Answer:

Both angles have a measure of 98 degrees, as they are congruent, and all angles must equal 360 degrees.

360- 164 = 196

196/2=98

8 0

2 years ago

If the circumference of a circle is x, then what is the area of the circle in terms of x?

grandymaker [24]

Answer:

x^2 / 4pi

Step-by-step explanation:

The area of a circle is (pi x r)^2

The circumference of a circle is 2pi x r

The find the radius, you need to divide x by 2pi, so x / 2pi

Then just plug it in as the radius:

(pi x (x / 2pi))^2 = x^2 / 4pi

7 0

3 years ago