M=(755-800) /30-12
m= -45/18 or -2.5
y-800 = -2.5(x-12)
y-800 = -2.5x + 30
y = -2.5x + 830
y = -2.5(120) + 830
y = 530 lbs
Answer:
this is a required equation.
Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So






Rounding up
We need a sample size of 564.
Answer: the mean number is of kittens is 4