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3 years ago

Consider the solution to the linear equation.

Mathematics

2 answers:

katen-ka-za [31]3 years ago

8 0

Well it technically won’t be be because it isn’t b

myrzilka [38]3 years ago

8 0

Answer:

the answer is b i think

Step-by-step explanation:

12345

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Find Sn for the given arithmetic series a1=-26 d=-9 n=24

ryzh [129]

Answer:

- 3108

Step-by-step explanation:

The sum to n terms of an arithmetic series is

$S_{n}$ = $\frac{n}{2}$ [ 2 $a_{1}$ + (n - 1)d ]

Substitute the given values into the formula

$S_{24}$ = $\frac{24}{2}$ [ (2 × - 26) + (23 × - 9) ]

= 12 ( - 52 - 207 )

= 12 × - 259 = - 3108

5 0

3 years ago

John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart

Rina8888 [55]

<h2>Answer:</h2>

$Probability=\frac{1}{24}$

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

$Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}$

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is $\frac{1}{24}$ </u></em>

3 0

3 years ago

1 large box is 18 sticks of clay how many does 55 large box equal

Anika [276]

It is equal to 825 sticks total

5 0

3 years ago

Read 2 more answers

Give two different sequences of three transformations that would map PQR onto EFG given that PQR=EFG.

Gre4nikov [31]

9514 1404 393

Answer:

Translate P to E; rotate ∆PQR about E until Q is coincident with F; reflect ∆PQR across EF
Reflect ∆PQR across line PR; translate R to G; rotate ∆PQR about G until P is coincident with E

Step-by-step explanation:

The orientations of the triangles are opposite, so a reflection is involved. The various segments are not at right angles to each other, so a rotation other than some multiple of 90° is involved. A translation is needed in order to align the vertices on top of one another.

The rotation is more easily defined if one of the ∆PQR vertices is already on top of its corresponding ∆EFG vertex, so that translation should precede the rotation. The reflection can come anywhere in the sequence.

<em>Additional comment</em>

The mapping can be done in two transformations: translate a ∆PQR vertex to its corresponding ∆EFG point; reflect across the line that bisects the angle made at that vertex by corresponding sides.

3 0

3 years ago

Read 2 more answers

Solve for x.<br> 8(x + 1) - 3(x + 4) = 7(2 - x)<br> Ox=11<br> Ox=-11<br> Ox= -1 1 /<br> Ox=11/

inna [77]

Answer:

1.5

Step-by-step explanation:

$8(x + 1) - 3(x + 4) = 7(2 - x) \\ 8 x + 8 - 3x - 12 = 14 - 7x \\ 8x - 3x + 7x = 14 - 8 + 12 \\ 12x = 18 \\ x = \frac{18}{12} \\ x = \frac{3}{2} \\ x = 1.5$

3 0

3 years ago

Read 2 more answers