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Elis [28]
3 years ago
9

What is the opposite of 8?

Mathematics
2 answers:
bonufazy [111]3 years ago
7 0

Answer is: -8

step by step is that all you have to do is add a negative symbol

hope this helps <em>:)</em>

user100 [1]3 years ago
7 0

Answer: 8 because the opposite of 8 is -8 and the opposite of that is 8 so yep 8 is the answer

Step-by-step explanation:

Brainiest please

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Write an equation for a parabola in which the set of all points in the plane are equidistant from the focus and line. F(–2, 0);
UNO [17]
The line is called the directrix.  Here we have a vertical directrix, so a parabola sideways from usual.

Geometry is best done with squared distances.  The squared distance from an arbitrary point (x,y) to the vertical line x=2 is (x-2)^2.

We equate that to the squared distance of (x,y) to the focus (-2,0): 

(x-2)^2 = (x - -2)^2 + (y - 0)^2

x^2 -4x + 4=x^2 +4x +4 + y^2

-8x = y^2

We could call that done.  A more standard form might be

x =- \dfrac 1 8 \ y^2

8 0
3 years ago
I need help please?!!!
malfutka [58]

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4 years ago
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Members of a soccer team raised $1946.50 to go to a tournament. They rented a bus
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3 years ago
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If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

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2 years ago
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